Question

我正在学习C ++。我的代码中的某些东西不起作用，但我不明白这是什么问题。我认为stat数组的增量计算T数组中重复的数量...我该如何解决？也许语法stat [elt] ++不正确？

#include <iostream>
#include <cctype>
#include <ctime>
#include <cstdlib>
#include <string>
#include <sstream>
using namespace std;


int anneeSecu(int T[12][13], int j){
// here I join the 2 numbers of tab (they refer to the year of birth) and I add the number 20, because I know that they were born all after 2000
        int a = T[j][1];
        int b = T[j][2];

        ostringstream oss;
        oss << "20" << a << b;
        istringstream iss(oss.str());
        int ab;
        iss >> ab;
        int annee = ab;
        cout << annee << endl;
        return annee;
    }




int main(){
    int T[12][13]={ {1,1,2,0,2,3,7,1,9,8,2,0,5},
                    {2,1,3,0,5,8,9,9,0,8,1,0,2},
                    {2,1,6,0,8,1,9,2,6,5,4,8,7},
                    {2,1,5,0,6,5,6,3,4,6,0,6,7},
                    {1,1,5,0,6,5,6,3,4,6,0,7,5},
                    {2,1,5,0,2,5,6,3,4,6,0,6,7},
                    {2,1,5,0,6,2,9,1,4,7,1,6,3},
                    {2,1,4,0,6,2,2,1,4,7,1,6,3},
                    {2,1,4,0,9,3,5,1,4,7,1,6,3},
                    {1,1,1,1,2,5,6,1,7,5,0,0,7},
                    {1,1,1,0,9,5,6,1,7,5,1,0,7},
                    {2,1,4,1,0,3,5,1,4,7,0,2,2} };


    int stat[6]={0,0,0,0,0,0};
    for (int i=0;i<12;i++){
        int l=anneeSecu(T,i);
        **stat[l]++;**
    }

return 0;
}

输出和冻结cmd

2012

Process returned -1073741819 (0xC0000005)   execution time : 1.764 s
Press any key to continue.

解错误在stat [l] ++中（因为它只需要从0到5的数字......）校正=＆gt; STAT [1- 2011] ++

Answer 1

这段代码存在问题：

int l=anneeSecu(T,i);
stat[l]++;

因为anneeSecu接缝返回的数字比数组的长度更大。 l必须介于0到5之间，否则您的程序将崩溃。

C ++学习在数组中重复多少个数字

1 个答案: