由于语法错误，SQLite prepare方法失败

Question

所以我想为Users创建一个数据库，并使用变量将值插入到字段中。最初我尝试使用它来调用do函数，但它没有正确读取变量所以我决定只使用prepare并单独执行。这是我的代码：

$dbh->do("DROP TABLE IF EXISTS Users");
$dbh->do("CREATE TABLE Users(
zid TEXT, 
Name TEXT, 
Email TEXT, 
password TEXT, 
Mates TEXT, 
Program TEXT, 
Courses TEXT, 
Suburb TEXT, 
Birthday TEXT)");

$zid = "z33432523";
$name = "John Doe";
$email = "email@gmail.com";
$password = "alien";
$mates = "z3459148 z3458291";
$program = "";
$courses = "";
$suburb = "";
$birthday = "13/5/1992";

$sth = $dbh->prepare('INSERT INTO Users VALUES (?, ?, ?, ?, ?. ?, ?, ?, ?)');
$sth->execute($zid, $name, $email, $password, $mates, $program, $courses, $suburb, $birthday);
$dbh->disconnect();

但是，如果我尝试运行此代码，则会收到以下错误：

DBD::SQLite::db prepare failed: near ".": syntax error at ./dbm.pl line 35.

我不确定问题到底是什么？

Answer 1

a