由于运行时语法错误而显示列表视图时出错

Question

如何解决SQLiteLog（3507）:( 1）在“=”附近：android中的语法错误sqlite。我的数据库可以正常运行错误。 logcat显示第1行中的语法错误。

public void openAndQueryDatabase()
 {
    try
 {          
db = openOrCreateDatabase( "mydatabase.db", SQLiteDatabase.CREATE_IF_NECESSARY , null ); 

        Cursor cursor = db.rawQuery("select * from "+ table + "where name='"+ name + "'",  null);  //line 1

        int count = cursor.getColumnCount();


        if (cursor != null )
        {
            if  (cursor.moveToFirst())
            {
                do 
                {
                     for (int i =0 ; i< count; i++)
                    {
                    String data = cursor.getString(i);
                    details.add(data);
                    }
                }
                while (cursor.moveToNext()); 
            } 
         }      

    }   
    catch (SQLiteException se )
    {   

        Log.e(getClass().getSimpleName(), "Error in the code");
    } 

    finally 
    {

            db.close();
    }

}

Answer 1

您的表名与where关键字之间需要一个空格：

Cursor cursor = db.rawQuery("select * from "+ table + " where name='"+ name + "'",  null);

还要考虑使用?绑定args用于文字，例如

Cursor cursor = db.rawQuery("select * from "+ table + " where name=?", new String[] { name });