Question

import urllib
import csv

@manager.command
def list_routes():
    for rule in app.url_map.iter_rules():
        options = {}

    for arg in rule.arguments:
        options[arg] = "[{0}]".format(arg)

    url = rule.rule
    line = urllib.parse.unquote("{}{} ".format(rule.endpoint, url))

    with open('urls.cvs', 'a') as out:
        spamwriter = csv.writer(out, lineterminator='', dialect='excel')
        spamwriter.writerows(line)
        spamwriter.writerows('\n')

我需要填写csv文件，以便rule.endpoint和url具有单独的列。

Answer 1

您的writerows参数只需要是该行应包含的值列表的列表。因此，例如writer.writerows([[1, 2], [3, 4]])将添加两行，其中每行包含两个值。当您只添加一行时，可以使用writerow：

spamwriter.writerow([rule.endpoint, url])

这是一个模型。我使用BytesIO，因此我不需要实际写入文件：

import csv
import io
c = io.BytesIO()
w = csv.writer(c, lineterminator="", dialect="excel")
w.writerow(['endpoint', 'url'])
print(c.getvalue())  # prints: endpoint,url

Answer 2

import csv
@manager.command
def list_routes():
    with open('urls.csv', 'w') as out:
        csv_writer = csv.writer(out, lineterminator='\n')
        csv_writer.writerows([[rule.endpoint, rule.rule] for rule in app.url_map.iter_rules()])

使用Python拆分CSV文件中列的值

2 个答案: