Question

我正在使用Python进行DS课程，他们要求我修复下一个功能。由于我正在学习Python并行编程以获取此类，所以我有点失去任何帮助。将不胜感激！

split_title_and_name

people = ['Dr. Christopher Brooks', 'Dr. Kevyn Collins-Thompson', 'Dr. VG Vinod Vydiswaran', 'Dr. Daniel Romero']

def split_title_and_name(person):
    return person.split()[0] + ' ' + person.split()[-1]

#option 1
for person in people:
    print(split_title_and_name(person) == (lambda person:???))

#option 2
#list(map(split_title_and_name, people)) == list(map(???))

Answer 1

根据功能的名称，我想你想要这个：

>>> people = ['Dr. Christopher Brooks', 'Dr. Kevyn Collins-Thompson', 'Dr. VG Vinod Vydiswaran', 'Dr. Daniel Romero']
>>> def split_title_and_name(people_list):
...     return [p.split('. ') for p in people_list]
...                    # ^ Assuming title will always be followed by dot '.',
                       # There will be only one '.' dot in the sample string

>>> split_title_and_name(people)
[['Dr', 'Christopher Brooks'],
#  ^     ^
# Title  Name 
 ['Dr', 'Kevyn Collins-Thompson'], 
 ['Dr', 'VG Vinod Vydiswaran'], 
 ['Dr', 'Daniel Romero']]

注意：而且你绝对不需要 lambda 。在任何情况下都不需要它。

Answer 2

list（map（map（title_and_name，people））== list（map（lambda person：person.split（）[0] +''+ person.split（）[-1]，people））

Answer 3

此项工作（：

people = ['Dr. Christopher Brooks', 'Dr. Kevyn Collins-Thompson', 'Dr. VG Vinod Vydiswaran', 'Dr. Daniel Romero']

def split_title_and_name(person):
    title = person.split()[0]
    lastname = person.split()[-1]
    return '{} {}'.format(title, lastname)

list(map(split_title_and_name, people))

Python中的Lambda和List Comprehensions

3 个答案: