Question

使用oracle数据库12 我有这个数据

C:\full\path\to\viewers\apps\maxq\

我想要的是在X2中找到共同的值，然后返回X1 在这种情况下，我想得到42974和42975，因为他们共享相同的X2

我使用此查询，但它不会返回任何内容

X1      X2              X3
42858   RRR08401000A    1
42858   RRR06113000A    1
42858   RRR05529000A    1
42858   RRR05529000B    1
42858   RRR49110RRRF    1
42858   34100000000A    1
42974   XYZ39916000A    1
42974   XYZ00949000B    2
42974   XYZ04888000A    1
42974   XYZ39915000B    1
42974   XYZ38535000A    1
42974   XYZ42350000A    1
42974   XYZ39746X0AA    1
42974   XYZ39743X0AA    1
42974   XYZ39923000A    1
42974   XYZ39745X0AA    1
42974   XYZ39744000A    1
42974   XYZ03058X0AB    1
42974   XYZ39759000A    1
42974   XYZ39760000B    1
42974   XYZ39762000A    1
42974   XYZ39748000A    1
42974   XYZ39749000B    1
42974   XYZ39747000A    1
42974   XYZ39742X0AA    1
42974   XYZ47965000B    1
42974   IUYI0902000E    1
42974   IUYI0897000F    1
42974   IUYI0909000F    1
42975   XYZ39916000A    1
42975   XYZ00949000B    2
42975   XYZ04888000A    1
42975   XYZ39915000B    1
42975   XYZ38535000A    1
42975   XYZ42350000A    1
42975   XYZ39746X0AA    1
42975   XYZ39743X0AA    1
42975   XYZ39923000A    1
42975   XYZ39745X0AA    1
42975   XYZ39744000A    1
42975   XYZ03058X0AB    1
42975   XYZ39759000A    1
42975   XYZ39760000B    1
42975   XYZ39762000A    1
42975   XYZ39748000A    1
42975   XYZ39749000B    1
42975   XYZ39747000A    1
42975   XYZ39742X0AA    1
42975   XYZ47965000B    1
42975   IUYI0902000E    1
42975   IUYI0897000F    1
42975   IUYI0909000F    1

但如果我从数据中删除了42858，则返回42974和42975

请告知

感谢，旅行男人

SELECT 
TT.X1
  FROM TEST12 TT
group by TT.WORK_ORDER 
having count(distinct TT.X2) = (select count (distinct tt2.X2) from TEST12 tt2)

Answer 1

尝试加入：

SELECT DISTINCT T1.X1
FROM TEST12 T1
JOIN TEST12 T2 ON T1.X2 = T2.X2
    AND T1.X1 != T2.X2

如果三个或更多行共享DISTINCT值，则需要X2。如果最多只有两个行共享X2值，则DISTINCT关键字可能会被省略。

Answer 2

我知道您希望X1值共享所有X2值。
此解决方案适用于Oracle 11g R2

以下是一些选项。 X2元素的数量有限制，因为它们被连接成一个字符串。

select    count (*)                                   as x2_within_group
         ,x2_elements
         ,listagg (x1,',') within group (order by x1) as x1_list


from     (select    X1
                   ,listagg (x2,',') within group (order by x2) as x2_list
                   ,count (*)                                   as x2_elements

          from      TEST12

          group by  X1
          )


group by  x2_list
         ,x2_elements
;

X2_WITHIN_GROUP  X2_ELEMENTS X1_LIST                      
---------------- ----------  ---------
2                23          42974,42975                   
1                6           42858

select    dense_rank () over (order by listagg (x2,',') within group (order by x2)) as group_id
         ,X1
         ,count (*)                                                                 as x2_elements
from      TEST12

group by  X1
;

  GROUP_ID      X1      X2_ELEMENTS
---------- ----------   ------------
         1      42858      6
         2      42975      23
         2      42974      23

在VIew中找到共同的价值观

2 个答案: