我尝试alert
在express.get中变量的字符串并执行res。我想要警惕这个"我正在工作取得"。
这是我的 server.js
var express = require('express');
var app = express();
app.use(express.static(__dirname + '/publicServer'));
app.get('/fimlList', function(req, res) {
console.log('i receive a GET request');
var tryFetch = {myString: 'I am working fetch'};
res.json(tryFetch)
})
app.listen(3000);
console.log('Server running on port 3000');
我的 App.js
import React from 'react';
var IchBinForm = require('./IchBinForm');
var SortFilms = require('./SortFilms');
var SearchFilm = require('./SearchFilm');
var FilmShort = require('./FilmShort.js');
var FilmLong = require('./FilmLong.js');
var App = React.createClass({
getInitialState: function() {
return {
list: {}
},
componentWillMount: function(){
var fromServer = fetch('/fimlList')
.then(function(response) {
return response.json()
})
.then(function(responseJson) {
return responseJson.myString
})
alert(fromServer);
},
changeShow: function(newShow, filmId) {...},
deleteFilm: function(id) {...},
seeForChangeInForm: function(change, id) {...},
addNewFilm: function() {...},
sortMe:function() {...},
searchMe: function(searchWord) {...},
howSearch:function(whichCheckBox, val) {...},
render: function() {
....
}
}
});
return (...);
}
});
module.exports = App;
我得到了什么:
我做错了什么?
答案 0 :(得分:5)
您为fromServer
分配来自获取的承诺...
您试图以同步方式编写代码,而事实上它是异步的
将代码移到最后then
函数
.then(function(responseJson) {
console.log(responseJson)
})
或使用async / await在编写代码时获得同步感觉
async function(){
var fromServer = await fetch('/fimlList')
.then(function(response) {
return response.json()
})
.then(function(responseJson) {
return responseJson.myString
})
alert(fromServer);
}
如果你采用异步/等待方法,我会建议更像这样的东西:
async function(){
let response = await fetch('/fimlList')
let responseJson = await response.json()
let fromServer = responseJson.myString
alert(fromServer)
}
答案 1 :(得分:2)
你没有消费你的承诺,试试:
componentWillMount: function(){
fetch('/fimlList')
.then(function(response) {
return response.json()
})
.then(function(responseJson) {
alert(responseJson.myString);
})
},