Question

这是输出1或0的代码，具体取决于2个数组的相等性

static void Main(string[] args)
        {

            while (true)
            {
                Console.WriteLine(Here());  
            }

这就是魔术发生的地方。

static int Here()
        {
            Random rnd = new Random();
            PlayerInput();
            int[] intarray = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 };
            string[] sarray = { "0", "1", "2", "3", "4", "5", "6", "7", "8", "9" };


                int i = rnd.Next(10); // creates a number between 1 and 10
                int x = rnd.Next(10);
                string iarray = intarray[x].ToString();
                if (iarray == sarray[i])
                {
                    return 1;
                }
                else
                {
                    return 0;
                }



        }

当两个数组不相等时输出0，反之亦然。现在我想计算它输出的次数0＆amp; 1。

问题：

我怎么能这样做？
我应该将输出传输到数组以便于操作吗？

Answer 1

除非我误解你的问题，否则你似乎只能有两个反变量：

static void Main(string[] args)
{
    int totalOnes = 0;
    int totalZeroes = 0;

    while (true) // need to replace this with something that will actually exit!!
    {
        int ret = Here();
        if (ret == 1) totalOnes++; else totalZeroes++;
        Console.WriteLine(ret);  
    }

    Console.WriteLine("Total Ones: {0} Total Zeroes: {1}", totalOnes, totalZeroes);
}

编辑：感谢L J指出您的while循环永远不会退出，因为您有while (true)。你需要解决这个问题。

Answer 2

像这样

static void Main(string[] args)
{
    var zeroCount = 0;
    var oneCount = 0;
    while (true)
    {
        var result = Here();
        if (result == 1) oneCount++;
        if (result == 0) zeroCount++;
        Console.WriteLine($"Actual result {result}, zero count {zeroCount}, One count {oneCount}");     
    }
}

Answer 3

static int Here()
        {

            Random rnd = new Random();
            PlayerInput();
            int[] intarray = { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 };
            string[] sarray = { "0", "1", "2", "3", "4", "5", "6", "7", "8", "9" };

                **var Count1 = 0;
                var Count0 = 0;**
                int i = rnd.Next(10); // creates a number between 1 and 10
                int x = rnd.Next(10);
                string iarray = intarray[x].ToString();
                if (iarray == sarray[i])
                {
                    **Count1++;**
                    return 1;
                }
                else
                {
                    **Count0++;**
                    return 0;
                }



        }

Count0将包含输出0的次数。

Count1将包含输出1的次数。

如何衡量次数0＆amp; 1发生

3 个答案: