如何在惯用scala中链接操作

时间:2016-10-24 00:10:47

标签: scala functional-programming

我想将一个正则表达式列表应用于字符串。我目前的方法不是很实用

我目前的代码:

  val stopWords = List[String](
    "the",
    "restaurant",
    "bar",
    "[^a-zA-Z -]"
  )

  def CanonicalName(name: String): String = {
    var nameM = name        
    for (reg <- stopWords) {
      nameM = nameM.replaceAll(reg, "")
    }

    nameM = nameM.replaceAll(" +", " ").trim
    return nameM
  }

2 个答案:

答案 0 :(得分:2)

我认为这可以满足您的需求。

def CanonicalName(name: String): String = {
  val stopWords = List("the", "restaurant", "bar", "[^a-zA-Z -]")
  stopWords.foldLeft(name)(_.replaceAll(_, "")).replaceAll(" +"," ").trim
}

答案 1 :(得分:0)

'replaceAll'有可能替换一个单词的一部分,例如:“thermal&amp; BBQ restaurant”被替换为“rmal becue”。如果您想要的是“热烧烤”,您可以首先拆分名称,然后逐字应用您的停用词规则:

def isStopWord(word: String): Boolean = stopWords.exists(word.matches)

def CanonicalName(name: String): String = 
    name.replaceAll(" +", " ").trim.split(" ").flatMap(n => if (isStopWord(n)) List() else List(n)).mkString(" ")