Question

有一张桌子：PS_POSITION_TBL

我们想在上面构建层次结构的想法

案例1：038,0418和114向143报告

案例2：346和202向114报告

所以最高级别是level1，这是143，然后038,0418,114是级别2，因为他们报告到级别1然后346和202是级别3并且它们属于 3级桶，他们报告到2级

这些可以达到8级（MAX）

我需要的是在Oracle中以下列格式获取数据的查询：

position_nbr      reports_to              descr        
 038              143                     DIRECTOR 
 0418             143                     ADVISOR                        
 114              143                     DG                              
 346              114                     Manager                        
 202              114                     Lead

Answer 1

以下查询将为您提供一个分层集，由LEVEL左侧填充：

SELECT LPAD(' ', level * 2, ' ') || TO_CHAR(position_nbr), descr
  FROM PS_POSITION_TBL
CONNECT BY PRIOR position_nbr = reports_to
START WITH reports_to IS NULL;

如果您对在单个列中显示级别（LEVEL）感到不满意，并且每个级别都需要一个列，则可以基于LEVEL使用PIVOT但它会使订购有问题。

Answer 2

select    level1,level2,level3,level4,level5,level6,level7,level8,descr

from     (select        level as n,position_nbr as id,descr,position_nbr

          from          (         select position_nbr ,reports_to ,descr from PS_POSITION_TBL 
                        union all select 143          ,null       ,'CEO' from dual
                        )  t

          start with    reports_to is null

          connect by    reports_to = prior position_nbr
          ) 
          pivot (max(position_nbr) for n in (1 as level1,2 as level2,3 as level3,4 as level4,5 as level5,6 as level6,7 as level7,8 as level8))
;

或

select    decode (n,1,position_nbr) as level1
         ,decode (n,2,position_nbr) as level2
         ,decode (n,3,position_nbr) as level3
         ,decode (n,4,position_nbr) as level4
         ,decode (n,5,position_nbr) as level5
         ,decode (n,6,position_nbr) as level6
         ,decode (n,7,position_nbr) as level7
         ,decode (n,8,position_nbr) as level8
         ,descr

from     (select          level as n,position_nbr,descr

          from          (         select position_nbr ,reports_to ,descr from PS_POSITION_TBL 
                      union all select 143          ,null       ,'CEO' from dual
                      )  t

          start with    reports_to is null

          connect by    reports_to = prior position_nbr
          ) 
;

需要对平面结果集中的分层数据进行SQL查询

2 个答案: