Question

我正在设计一个应用程序：Eclipse，Jsf，Hibernate，WildFly，Primefaces。

而且我遇到了“未映射”的休眠问题，是的，我知道我们应该使用表名的实体名称。我是新来的，不确定如何正确处理。

自动创建的表是aluno_turma，尽我所能，对此表无能为力。

我查看了所有关于“未映射”的问题的答案，并尝试了所有问题，但无法使其发挥作用。

感谢您的帮助。

代码如下：

Aluno.java

@Entity
@ManagedBean
@Table(name = "Aluno")
public class Aluno implements Serializable {

    /**
     * 
     */
    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy=GenerationType.IDENTITY) 
    private Integer id;
...
    @ManyToMany
    @JoinTable(name="aluno_turma",
            joinColumns={           @JoinColumn(name="aluno_id")},
            inverseJoinColumns={    @JoinColumn(name="turma_id")})
    private List<Turma> turmas = new ArrayList<Turma>();

...
    public Integer getId() {
        return id;
    }
    public void setId(Integer id) {
        this.id = id;
    }

Turma.java

    @Entity
    @ManagedBean
    public class Turma implements Serializable{

        /**
         * 
         */
        private static final long serialVersionUID = 1L;
        @Id
        @GeneratedValue(strategy=GenerationType.IDENTITY) 
        private Integer id;
        private String  nome;
        private Integer diaSemana;
        private String  hora;
        private String  observacao;
        private Boolean inativo;

        @ManyToOne
        private Modalidade modalidade;

        @ManyToMany
        @JoinTable(name="aluno_turma",
                joinColumns={           @JoinColumn(name="turma_id")},
                inverseJoinColumns={    @JoinColumn(name="aluno_id")})
        private List<Aluno> alunos = new ArrayList<Aluno>();
    ...
        public Integer getId() {
            return id;
        }
        public void setId(Integer id) {
            this.id = id;
        }

alunoMBean.java

@ManagedBean(name="alunoBean")
@SessionScoped
public class AlunoMBean implements Serializable {
...
    private List<Turma> turmas;
...
    public List<Turma> getTurmas() {
        if(this.aluno.getNome() == null) {
            List<Turma> listTurma = new ArrayList<Turma>();
            return listTurma;
        }
        if(this.turmas == null) { //Só busca na tabela a primeira vez da consulta
            this.turmas = alunoDao.getTurmas(aluno, flagTurma);
        }
        return this.turmas;
    }

alunoDao.java

public List<Turma> getTurmas(Aluno aluno, Boolean flag) {

    List<Turma> turmas = new ArrayList<Turma>();
    turmas = em.createQuery("from Turma where inativo = 0 and id in ( select turma_id from aluno_turma where aluno_id = "+ aluno.getId()+" ) order by nome ", Turma.class).getResultList();
    //That doens't work: Not Mapped

    //turmas = em.createQuery("from Turma order by nome ", Turma.class).getResultList();
    //That works

    return turmas;
}

错误

01:43:16,105 ERROR [org.jboss.as.ejb3.invocation] (default task-14) WFLYEJB0034: EJB Invocation failed on component AlunoDao for method public java.util.List br.com.mvtech.alumni.dao.AlunoDao.getTurmas(br.com.mvtech.alumni.modelo.Aluno,java.lang.Boolean): javax.ejb.EJBException: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: aluno_turma is not mapped [from br.com.mvtech.alumni.modelo.Turma where inativo = 0 and id in ( select turma_id from Aluno_turma where aluno_id = 2 ) order by nome ]
at org.jboss.as.ejb3.tx.CMTTxInterceptor.handleExceptionInOurTx(CMTTxInterceptor.java:187)
at org.jboss.as.ejb3.tx.CMTTxInterceptor.invokeInOurTx(CMTTxInterceptor.java:277)

Answer 1

您正在创建JPQL查询，但使用的是SQL字段。 JPQL确实使用Object结构来表示语法而不是表结构。

您可以尝试以下操作：

Query query = em.createQuery("FROM Turma WHERE inativo = false and :aluno MEMBER OF alunos order by nome");
query.setParameter("aluno", aluno);
query.getResultList();

ManyToMany org.hibernate.hql.internal.ast.QuerySyntaxException“not mapped”

1 个答案: