Question

我们有一个应用程序，通过orm.xml文件完成映射，现在尝试添加注释。是否可以将两者结合起来。

persistence.xml

<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
    version="2.0">
    <persistence-unit name="disc" transaction-type="JTA">
        <jta-data-source>disc.jdbc.DataSource.OLTP</jta-data-source>

        <!--  List of Mapping files -->
        <mapping-file>META-INF/discCommon.orm.xml</mapping-file>
        <mapping-file>META-INF/discTerminology.orm.xml</mapping-file>

        <class>com.model.correspondence.Employees</class>
         <class>com.model.correspondence.AbstractEmployees</class>   
      </persistence-unit>
</persistence>

在实体类

中

@Entity
@Table(name = "TEST", schema="company") 
public class Employees extends AbstractEmployees{

private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = IDENTITY)
    @Column(name = "EMPLOYEE_ID", unique=true, nullable = false)
    private long employeeId;

    @Column(name = "DESCRIPTION",  nullable = false)
    private String description;

Serivceclass

private static final String SEARCH_FROM_ALL_EMPLOYEES= " select o from " +  Employees.class.getSimpleName()+ " o WHERE " +
    " upper(o.description) LIKE :desc";

Query query = entityManager.createQuery(SEARCH_FROM_ALL_EMPLOYEES);
        query.setParameter("desc", "%" + desc.toUpperCase() + "%");
        @SuppressWarnings("rawtypes")
        List employeeList= query.getResultList();

orm.xml文件正在运行，但注释实体类未被映射。以下是错误

引起：org.hibernate.hql.internal.ast.QuerySyntaxException：没有映射Employees [从Employees中选择o o WHERE upper（o.description）LIKE：desc] * 在org.hibernate.hql.internal.ast.util.SessionFactoryHelper.requireClassPersister（SessionFactoryHelper.java:180）在org.hibernate.hql.internal.ast.tree.FromElementFactory.addFromElement（FromElementFactory.java:110）在org.hibernate.hql.internal.ast.tree.FromClause.addFromElement（FromClause.java:93）在org.hibernate.hql.internal.ast.HqlSqlWalker.createFromElement（HqlSqlWalker.java:324）在org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromElement（HqlSqlBaseWalker.java:3420）在org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromElementList（HqlSqlBaseWalker.java:3309）

由于

Answer 1

也许您可以尝试在persistence.xml

中添加此行

<exclude-unlisted-classes>false</exclude-unlisted-classes>

有时，由于我们项目的配置不同，生成的类在路径中没有被JPA（以及您使用的实现）可以自动扫描。

所以，就我而言，我使用该行来告诉JPA实现必须映射我放在persistence.xml中的类，并且不要等到自动扫描。

在这种情况下，persistence.xml的可能性为

<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
    version="2.0">
    <persistence-unit name="disc" transaction-type="JTA">
        <jta-data-source>disc.jdbc.DataSource.OLTP</jta-data-source>

        <!--  List of Mapping files -->
        <mapping-file>META-INF/discCommon.orm.xml</mapping-file>
        <mapping-file>META-INF/discTerminology.orm.xml</mapping-file>

        <exclude-unlisted-classes>false</exclude-unlisted-classes>
        <class>com.model.correspondence.Employees</class>
        <class>com.model.correspondence.AbstractEmployees</class>   
      </persistence-unit>
</persistence>

我希望，这对你有用......

org.hibernate.hql.internal.ast.QuerySyntaxException：未映射Employees

1 个答案: