Question

我想从NetworkActivity_5851_*_09-04-2016.done获取NetworkActivity_5851_2326316_09-04-2016.log.gz字符串，这里是我写的代码

local file="$1"
local extension="${file##*.}"
if [ $extension = 'done' ]; then
   local files=`basename $file`
   files="${files#*_}"
   files="${files#*_}"
   files="${files%_*}"
   local q=_"$files"_
   local mask="${file/done/log.gz}"
   mask="${mask/${q}/_*_}"
   r=`ls "${mask}" | wc -l`

并且它工作正常，但是当我用python脚本运行它时它失败了。我的意思是r变量有错误的值。这是Python中的代码

    shell = Shell(RUN_SCRIPT_2, LOGFILE)

Shell是

class Shell():
    """
    Base class for the shell script object which
    is under testing.
    """

    def __init__(self, path_to_script, path_to_log=None):
        """
        executes shell script and store results
        of STDOUT and STDERR into appropriate attributes
        """
        self.path_to_log = path_to_log
        # clear log file before run
        if self.path_to_log:
            open(self.path_to_log, 'w').close()

        shell = subprocess.Popen([path_to_script],
                                 stdout=subprocess.PIPE,
                                 stderr=subprocess.PIPE,
                                 shell=True)
        # the line below makes sure shell command execution finished
        self.stdout, self.stderr = shell.communicate()
        self.log_data = self.get_log_data()

和文件path_to_script是

echo 'Start' 
file="${SOURCE_DIR}/NetworkActivity_5851_3_09-04-2016.done"
    extension="${file##*.}"
    if [ $extension = 'done' ]; then
       files=`basename $file`
       files="${files#*_}"
       files="${files#*_}"
       files="${files%_*}"
       q=_"$files"_
       mask="${file/done/log.gz}"
       mask="${mask/${q}/_*_}"
       r=`ls "${mask}" | wc -l`
       echo $r
       if [ $r = $files ]; then
          rez=0
       else rez=1
       fi    
fi
if [[ $rez -eq 1 ]]; then
        echo "Failure"
else echo "Success"
fi
echo 'Finish'

因此，当我从终端r运行path_to_script时，变量设置文件数量，当我使用Python运行它时，它设置为0.

Answer 1

你可以单独使用bash字符串操作技术来做到这一点。

$ inputString="NetworkActivity_5851_2326316_09-04-2016.log.gz"
$ substring="${inputString%%.*}"                                      # Removing the part after the first '.'
$ [[ $substring =~ .*_([[:digit:]]+)_.* ]] && NUM=${BASH_REMATCH[1]}  # Extracting the number you want to replace 
$ finalString="${substring/$NUM/*}.done"                              # Forming the final string with the extension

$ printf "%s\n" "$finalString"
NetworkActivity_5851_*_09-04-2016.done

您可以将此逻辑放在一个shell脚本中，并为您拥有的多个文件运行相同的逻辑。上述命令可以直接在控制台上运行。

Answer 2

好吧，我基于你的第一段。希望我遇到了问题！这是我使用Perl和带有简单命令行的正则表达式的解决方案。

~$ gunzip NetworkActivity_5851_2326316_09-04-2016.log.gz && perl  -e 'while(<>){print $_ if $_ =~ /NetworkActivity_\d+_.*_\d{2}\-\d{2}-\d{4}\.done/}' NetworkActivity_5851_2326316_09-04-2016.log

希望它有所帮助！

使用shell解析字符串

2 个答案: