if语句,用于确定用户是否输入了可以使用的变量,如果没有输出错误消息
当用户通过enterMoneyAmount输入字符时,如果它是一个完成代码的数字,如果不是数字打印错误消息到moneyResults
import UIKit
class ViewController: UIViewController {
var fee: Double = Double(1.20)
var tax: Double = Double(1.07)
var deposit: Double = Double(100)
// set values needed for the calculator to function
@IBOutlet weak var moneyResults: UILabel! //The resulting text applied once the button is pressed
@IBOutlet weak var enterMoneyAmount: UITextField! // Input from the users keyboard
@IBAction func buttonPressed(_ sender: AnyObject) {
let enteredAmountString = enterMoneyAmount?.text ?? ""
let enteredAmount: Double = Double(enteredAmountString) ?? 0
//if enteredAmount: Double == Double("") {
let mDeposit = enteredAmount - deposit
let mDepositAndFee = mDeposit / fee
let mDepositAndFeeAndTax = mDepositAndFee / tax
moneyResults.text = "$ " + String(mDepositAndFeeAndTax)
// } else {
// moneyResults.text = String("Please enter a valid whole number")
// }
}
答案 0 :(得分:0)
你可以试试这个:
guard let enteredAmount = Double(enteredAmountString) else {
moneyResults.text = "You did not enter a number."
}
您还可以将文本字段的键盘类型设置为数字/小数点,以防止用户输入任何其他内容。
答案 1 :(得分:0)
if
let enteredAmountString = enterMoneyAmount.text,
let enteredAmount = Double(enteredAmountString)
{
let mDeposit = enteredAmount - deposit
let mDepositAndFee = mDeposit / fee
let mDepositAndFeeAndTax = mDepositAndFee / tax
moneyResults.text = "$ \(mDepositAndFeeAndTax)"
}
else
{
moneyResults.text = String("Please enter a valid whole number")
}