import random
cards_names = {1: "Ace", 2: "2", 3: "3", 4: "4", 5: "5", 6: "6", 7: "7", 8: "8",
9: "9", 10: "10", 11: "Jack", 12: "Queen", 13: "King"}
def dealing():
return random.randint(1, 13)
def value_of_hand(cards):
value = 0
for card in cards:
if 1 < card <= 10:
value += card
elif card > 10:
value += 10
if 1 in cards and value + 11 <= 21:
return value + 11
elif 1 in cards:
return value + 1
else:
return value
def your_hand(name , cards):
faces = [cards_names[card] for card in cards]
value = value_of_hand(cards)
if value == 21:
print ("Wow, you got Blackjack!")
else:
print ("")
print ("%s's hand: %s, %s : %s %s") % (name, faces[0], faces[1], value)
for name in ("Dealer", "Player"):
cards = (dealing(), dealing())
your_hand(name, cards)
答案 0 :(得分：1)
我在这里假设您使用的是Python 3.x并收到此错误：
TypeError：％不支持的操作数类型：'NoneType'和'tuple'
您需要在打印括号内的％之后移动部件以避免错误。此外，您的打印件中有一个<!DOCTYPE html>
<html>
<head>
<textarea rows="10" cols="50" maxlength = "20000" id = "textContent">Content</textarea>
<style>
table {
width: 100%;
border-collapse: collapse;
}
table, td, th {
border: 1px solid black;
padding: 5px;
}
th {text-align: left;}
</style>
</head>
<body>
<?php
$q = intval($_GET['q']);
$con = mysqli_connect('localhost','root','gwatchgwatch63','mdmmp');
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
mysqli_select_db($con,"jvrs");
$sql="select objectID,objectTextLine from objecttextline where objectID = '".$q."' order by objectTextLineOrder";
echo "SQL::".$sql;
$result = mysqli_query($con,$sql);
$textContent[0] = " ";
$textContent[1] = " ";
$textContent[2] = " ";
$textContent[3] = " ";
$textContent[4] = " ";
$textContent[5] = " ";
$i=0;
while($i < 6 and $row = mysqli_fetch_array($result)) {
$textContent[$i] = $row['objectTextLine'] ;
echo $textContent[$i];
}
mysqli_close($con);
?>
<button onclick={document.getElementById("textContent").value="<?php echo $textContent[0]; ?>";}>query</button>
<button
onclick={x=document.getElementById("textContent").value;alert(x);}>query1</button>
</body>
</html>
太多。删除它，然后打印正常：
%s经销商的手：王牌，8：19球员的手：9,7：16
如您所见，print ("%s's hand: %s, %s : %s" % (name, faces[0], faces[1], value))
：s的数量应该等于您提供给它的参数。如果不删除额外的％s，它将在Python 3上打印以下错误：
TypeError：格式字符串
的参数不足
此外，在Python 3中，您可以使用新的字符串格式化语法：
%s它有时比使用％s的字符串插值的旧方式更灵活，并且当然有用的功能。