Question

如何使用Oracle sql从下表中提取具有最新结束日期的唯一名称。

NAME    Start DATE  End Date
ATO210291676    21/11/2015  18/05/2016
ATO210291676    19/05/2016  30/06/2017
ATO210291889    21/11/2015  18/05/2016
ATO210291889    19/05/2016  30/06/2017
ATO210291923    21/11/2015  18/05/2016
ATO210291923    19/05/2016  30/06/2017
ATO210186276    25/05/2015  24/05/2016
ATO210186276    25/05/2016  30/06/2017
ATO210186373    25/05/2015  24/05/2016
ATO210186373    25/05/2016  30/06/2017
TNT212498119    29/06/2015  28/06/2016
TNT212498119    29/06/2016  30/06/2017
TNT212498349    26/02/2016  30/06/2017
ATO212491256    26/02/2016  30/06/2017
ATO212502235    26/02/2016  30/06/2017
ATO212522556    26/02/2016  30/06/2017
ATO212522582    26/02/2016  30/06/2017
CVE114AK0076    16/09/2015  26/06/2016
CVE114AK0076    27/06/2016  30/06/2017
CVE414AK0012    15/09/2015  26/06/2016
CVE414AK0012    27/06/2016  30/06/2017

我试图产生以下结果。

ATO210291676    19/05/2016  30/06/2017
ATO210291889    19/05/2016  30/06/2017
ATO210291923    19/05/2016  30/06/2017
ATO210186276    25/05/2016  30/06/2017
ATO210186373    25/05/2016  30/06/2017
TNT212498119    29/06/2016  30/06/2017
TNT212498349    26/02/2016  30/06/2017
ATO212491256    26/02/2016  30/06/2017
ATO212502235    26/02/2016  30/06/2017
ATO212522556    26/02/2016  30/06/2017
ATO212522582    26/02/2016  30/06/2017
CVE114AK0076    27/06/2016  30/06/2017
CVE414AK0012    27/06/2016  30/06/2017

结果集应该如上所述

Answer 1

SELECT NAME, MAX(ENDDate)
from tab
GROUP BY NAME

您可以使用max功能获取最新日期。

Answer 2

SELECT Name, StartDate, EndDate
FROM [Your_Table] A
INNER JOIN 
(
    SELECT Name, MAX(EndDate) AS MaxEndDate
    FROM [YOUR_TABLE]
    GROUP BY Name
) B ON A.Name = B.Name AND A.EndDate = B.EndDate

Answer 3

select      NAME
           ,"Start DATE"
           ,"End Date"           

from       (select      t.*
                       ,row_number () over (partition by NAME order by "End Date" desc) as rn

            from        t
            ) t

where       rn = 1
;

Answer 4

您可以在一次传递中获得所需的结果，而无需连接或子查询。通过在实际数据上尝试不同的解决方案，您是否可以确定这是否可以提高速度。

select   name, 
         max(start_date) keep (dense_rank last order by end_date) as start_date, 
         max(end_date) as end_date
from     table_name
group by name
;

如何获取每个名字的最后一行？

4 个答案: