Question

我有两张桌子：

    materials:
      int id
     text title

   costs:
     int id
     int material_id
     int cost
datetime created_at

数据：

    materials:
1 Wood
2 Steel
3 ...

costs:
1,1,200,2015-07-02
2,1,205,2015-07-03
3,1,210,2015-07-04

我想获得最后费用的材料。像这样：

id title cost
1  Wood  210

我试试这个：

select materials.id, title, cost from materials 
left join (
  select * from costs
  order by costs.id DESC
) as costs on costs.material_id = materials.id
group by materials.id

和此：

select materials.id, materials.title, c1.cost from costs c1
    join (select material_id, max(id) as id from costs group by material_id) AS c2
        on c1.id = c2.id
left join materials on materials.id = c1.material_id

但有时费用（！）不正确。

这会返回一个值的正确成本：

    select cost, material_id
  from costs
    where material_id = 2
      order by id DESC
        limit 1

现在我只是获取材料列表并获得php foreach循环的成本（每行+1个查询）

请帮助我！

Answer 1

select m.id, m.title, c1.cost 
from materials m
join costs c1 on c1.material_id = m.id
join 
(
  select material_id, max(created_at) as dt
  from costs
  group by material_id
) c2 on c2.material_id = m.id and c2.dt = c1.created_at

获取每行的最后费用

1 个答案: