Question

我有点困惑为什么在我的表单上'clickjacking middleware` trowing 属性错误。

我正在制作一个简单的应用程序来收集人工或用户信息，我面临一个小问题，有人可以帮助我并澄清此代码中的错误

来自我的Traceback的

Dpaste，这是我的观点

class PersonalInfoView(FormView):
    """TODO: CreateView for PersonalInfoForm
    return: TODO
    """
    template_name = 'apply_to/apply_now.html'
    form_class = PersonalInfoForm
    success_url = 'success/'

    def get(self, form, *args, **kwargs):
        """TODO: define get request
        return: TODO
        """
        self.object = None
        form_class = self.get_form_class()
        form = self.get_form(form_class)
        return self.render_to_response(
            self.get_context_data(form=form))

    def post(self, form, *args, **kwargs):
        """TODO: Post request for PersonalInfoForm
        return: TODO
        """
        self.object = None
        form_class = self.get_form_class()
        form = self.get_form(form_class)
        if form.is_valid():
            return self.form_valid(form)
        else:
            return self.form_class(form)

    def form_valid(self, form, *args, **kwargs):
        """TODO: Validate form
        return: TODO
        """
        self.object = form.save()
        return HttpResponseRedirect(self.get_success_url())

    def form_invalid(self, form, *args, **kwargs):
        """TODO: handle invalid form request
        return: TODO
        """
        return self.render_to_response(
            self.get_context_data(form=form))

网址

"""superjobs URL Configuration

the `urlpatterns` list routes URLs to views. For more information please see:
    https://docs.djangoproject.com/en/1.8/topics/http/urls/
examples:
function views
    1. Add an import:  from my_app import views
    2. Add a URL to urlpatterns:  url(r'^$', views.home, name='home')
class-based views
    1. Add an import:  from other_app.views import Home
    2. Add a URL to urlpatterns:  url(r'^$', Home.as_view(), name='home')
including another URLconf
    1. Add a URL to urlpatterns:  url(r'^blog/', include('blog.urls'))
"""
from django.conf.urls import include, url
from django.contrib import admin
from django.views.generic import TemplateView

from labor_apply_app.views import PersonalInfoView

urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),
    # django-contrib-flatpages

    # url(r'^apply_to/', include('labor_apply_app.urls')),
    url(r'^$', 'labor_apply_app.views.index', name='index'),

    url(r'^apply_now/$', PersonalInfoView.as_view()),
    url(r'^success/$', TemplateView.as_view()),

    #  Django Allauth
    url(r'^accounts/', include('allauth.urls')),
]

Answer 1

您的追溯表明您还没有使用上面的视图，而是使用了表单。大概你在urls.py中分配了错误的东西。

编辑实际上问题是，当表单无效时，post方法会返回表单本身，而不是HttpResponse。

但是，你应该不定义任何这些方法。您只是复制基于类的视图已经应该为您做的事情。使您的视图实际上从CreateView继承并完全删除所有这些方法定义。

PersonalInfoForm的属性错误

1 个答案: