如何在每个字符相同时从列表中删除元素（Python）？

Question

sample = ['AAAA','ABCB','CCCC','DDEF']

我需要消除元素中每个字符与其自身相同的所有元素，例如。 AAAAA，CCCCC

output = ['ABCB','DDEF']

sample1 =[]
for i in sample:
    for j in i:
       if j == j+1:    #This needs to be corrected to if all elements in i identical to each other i.e. if all "j's" are the same
        sample1.pop(i)

打印样本

Answer 1

 sample = ['AAAA','ABCB','CCCC','DDEF']
 output = [sublist for sublist in sample if len(set(sublist)) > 1]

编辑回答评论。

sample = [['CGG', 'ATT'], ['ATT', 'CCC']]
output = []
for sublist in sample:
    if all([len(set(each)) > 1 for each in sublist]):
        output.append(sublist)

# List comprehension (doing the same job as the code above)
output2 = [sublist for sublist in sample if 
           all((len(set(each)) > 1 for each in sublist))]

Answer 2

sample = ['AAAA','ABCB','CCCC','DDEF']

sample1 = []
for i in sample:
    if len(set(i)) > 1:
        sample1.append(i)