Question

我正在学习python并尝试了anagram generator练习，然后决定尝试不同的方法来生成anagrams，然后决定生成sub anagrams。我遇到的问题是需要比较列表，然后需要从list_1中删除list_2以说明它是否是一个子字谜，但这不会发生，当我运行它时，第一个字母被删除，然后一个字母，两个词都是一样的。我的代码如下：

def sub_anagram(word_1, word_2): 
        #letters need to be sorted into alphabetical order
        list_1 = [c for c in word_1] #turns the string into a list
        #list_1.sort() #sorts the list alphabetically
        print(list_1) 
        list_2 = [c for c in word_2] #turns the string into a list
        #list_2.sort() #sorts the list alphabetically
        print(list_2)

        #then the lists get compared  
        #loop to check if any letters from list_2 are in list_1
        for list_2 in list_1: 
        #removes the letters in list_1 that are in
        list_1.remove(list_2)  list_2       
        print(list_2)
        print(list_1)
        list_1[len(list_1)-1] #checks the length of the list
        if list_2 == list_1:           
            print("It is a sub-anagram")#return true if it is a sub-anagram
        else:
            print("It is not a sub-anagram") #return false if not 

print("Sub-Anagram Antics")

#user inputs two words
#user input word 1
word_1 = input("Enter a word: ") 
#user input word 2
word_2 = input("Enter a word: ")


#call function 
sub_anagram(word_1, word_2)

Answer 1

这里有一些格式错误的python代码：

    for list_2 in list_1:  ## <<< == nothing indented under the for loop, meaning that the for loop is not actually looping

    #removes the letters in list_1 that are in
    list_1.remove(list_2)  list_2        ### <<<  Here you have a dangling expression, the second instance of "list_2"

为了让你的代码更具可读性，我认为你的for循环应该看起来像

    for ch in list_1:
        list2.remove(ch)

我们的想法是，当它不是列表时，你不应该将你的循环变量“list_2”标记出来......它是列表中的一个元素。

Answer 2

这就是你要找的东西：

def sub_anagram(word_1, word_2):
        #letters need to be sorted into alphabetical order
        list_1 = list(word_1) #turns the string into a list
        #list_1.sort() #sorts the list alphabetically
        print(list_1)
        list_2 = list(word_2) #turns the string into a list
        #list_2.sort() #sorts the list alphabetically
        print(list_2)

        #then the lists get compared
        #loop to check if any letters from list_2 are in list_1
        try:
            for letter in list_2:
                list_1.remove(letter)
            print('It is a sub-anagram')
        except ValueError:
            print('It is not a sub-anagram')

#user inputs two words
#user input word 1
word_1 = input("Enter a word: ")
#user input word 2
word_2 = input("Enter a word: ")


#call function
sub_anagram(word_1, word_2)

另外，正如其他人所指出的，你应该小心你的变量名。您的代码在不同的时间为名称list_2分配了不同的值。列表中的项目与列表本身不同。

如何从另一个字符列表中删除字符列表

2 个答案: