Question

使用以下函数和存储过程，我得到一个包含2列的结果集。我需要额外的是所有未结发票内部得分范围的第三列总数任何想法都会很棒。

  ALTER FUNCTION dbo.OpenOrders
    (
    @MandantId int
    )
  RETURNS TABLE
  AS
  RETURN
  SELECT        SUM(Invoices.Amount - ISNULL(Payment.Amount, 0)) AS Op
  FROM            Invoices INNER JOIN
                           Orders ON Invoices.OrderId = Orders.OrderId LEFT  OUTER JOIN
                           Payment ON Invoices.InvoiceId = Payment.InvoiceId
  WHERE        (Orders.MandantId = @MandantId)
  GROUP BY Invoice.InvoiceId, Invoices.Amount
  HAVING        (SUM(Invoices.Amount - ISNULL(Payment.Amount, 0)) <> 0)


  ALTER PROCEDURE dbo.GetOpRanges
  @MandantId int
  AS
  BEGIN

    SELECT * INTO #tmp_ranges

    FROM

    //wrong in first post -> OPDebitorByMandant(@MandantId)
    OpenOrders(@MandantId)

    SELECT  op AS [score range], COUNT(*) AS [number of occurences]
    FROM
    (SELECT CASE
      WHEN op BETWEEN 0 AND 50 THEN '  0- 50'
      WHEN op BETWEEN 50 AND 100 THEN ' 50-100' 
      WHEN op BETWEEN 100 AND 500 THEN '100-500' 
      ELSE '500 and >' END AS op
    FROM [#tmp_ranges]) AS t

    GROUP BY op

    RETURN

Result:
score range number of occurences range
------------------+-------------
  0- 50            23
 50-100            4
100-500            4
500 and >          21

What i need additional is a third column total for all open invoices inner score range.

Target result:
score range number of occurences Total
-----------+--------------------+------
  0- 50            23             1.150
 50-100            4                400
100-500            4              2.000
500 and >          21            22.000

      Tables:                                                                                                                                                                                 
    Invoices 
    InvoiceId  CustomerId OrderId DateOfInvoice Amount
    ----------+----------+-------+-------------+------
    1          1           20      20160301      1000.00
    2          2           22      20160501      2000.00
    3          1          102      20160601      3000.00
    ...

    Orders
    OrderId MandantId CustomerId DateOfOrder Amount
    -------+---------+----------+-----------+-----------
     20     1         1          20160101     1000.00
     22     1         2          20160101     2000.00
    102     1         1          20160101     3000.00
    ...

    Payment
    PaymentId MandantId CustomerId InvoiceId OrderId DateOfPayment Amount 
    ---------+---------+----------+---------+-------+-------------+-------------
    1         1         1          1          20     20160310      1000.00
    2         1         2          2          22     20160505      2000.00
    3         1         1          3         102     20160610      3000.00
    ...

希望它有用，并提前感谢任何解决方案

SQL Group按范围和总列数

0 个答案: