我想构建一个包含三个pickerviews的viewcontroller(它有三个相同的选项)。我在如何向标签显示一个特定行时遇到问题。我的代码:
我改变了其他部分仍然出错。编辑变量的首字母为小写。
@IBOutlet weak var picker1: UIPickerView!
@IBOutlet weak var picker2: UIPickerView!
@IBOutlet weak var picker3: UIPickerView!
var Array = ["Shake","Swipe Up","Swipe Right"]
@IBOutlet weak var label1: UILabel!
@IBOutlet weak var label2: UILabel!
@IBOutlet weak var label3: UILabel!
var placementAnswer = 0
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
picker1.delegate = self
picker1.dataSource = self
picker1.tag = 1
picker2.delegate = self
picker2.dataSource = self
picker2.tag = 2
picker3.delegate = self
picker3.dataSource = self
picker3.tag = 3
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
return Array[row]
}
func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
return Array.count
}
func numberOfComponents(in pickerView: UIPickerView) -> Int {
return 1
}
@IBAction func save3(_ sender: AnyObject) {
}
@IBAction func save2(_ sender: AnyObject) {
}
@IBAction func save1(_ sender: AnyObject) {
if (placementAnswer == 0){
label1.text = "Shake"
}
else if(placementAnswer == 1){
label1.text = "Swipe Up"
}
else{
label1.text = "Swipe Right"
}
if (placementAnswer == 0){
label2.text = "Shake"
}
else if(placementAnswer == 1){
label2.text = "Swipe Up"
}
else{
label2.text = "Swipe Right"
}
if (placementAnswer == 0){
label3.text = "Shake"
}
else if(placementAnswer == 1){
label3.text = "Swipe Up"
}
else{
label3.text = "Swipe Right"
}
}
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
picker1.delegate = self
picker1.dataSource = self
picker1.tag = 1
picker2.delegate = self
picker2.dataSource = self
picker1.tag = 2
picker3.delegate = self
picker3.dataSource = self
picker1.tag = 3
}
func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
if pickerView.tag == 1 {
// do things for pickerview 1
label1.text = row
}
else if pickerView.tag == 2 {
// do things for pickerview 2
label2.text = row
}else {
// do for pickerview 3
}
placementAnswer = row
}
}
答案 0 :(得分:0)
使用tag
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
picker1.delegate = self
picker1.dataSource = self
picker1.tag = 1
picker2.delegate = self
picker2.dataSource = self
picker1.tag = 2
picker3.delegate = self
picker3.dataSource = self
picker1.tag = 3
}
所以在你的委托方法中只需检查标签
func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
return Array[row]
}
func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
if pickerView.tag == 1 {
// do things for pickerview 1
Label1.text = Array[row]
}
else if pickerView.tag == 2 {
// do things for pickerview 2
Label2.text = Array[row]
}else {
// do for pickerview 3
}
}
答案 1 :(得分:0)
在这里你是@ h44f33z。我如何让每个部分相互依赖?例如,如果我为行为名称1选择“摇动”,它将不适用于行为名称2和3.每个行为名称部分将有一个相应的操作。谢谢!