Question

我一直在搜索论坛，没有任何帮助。我在一个视图控制器中使用4个文本字段，对于每个文本字段，我使用单独的pickerView作为textFields（4pickers）的inputViews。

当我点击第一个textField时，pickerView1成功出现，textfield显示数据，但是当我点击第二，第三和第四个文本字段时，会出现第一个pickerView。我怀疑错误在于inputView声明。

如果你能帮助在pickerView中添加一个“完成”按钮，我将非常感激。

我的代码：

class ViewController1: UIViewController, UIPickerViewDelegate
{

    @IBOutlet var pickerView1: UIPickerView!
    @IBOutlet var pickerView2: UIPickerView!
    @IBOutlet var pickerView3: UIPickerView!
    @IBOutlet var pickerView4: UIPickerView!

    @IBOutlet var textField1: UITextField!
    @IBOutlet var textField2: UITextField!
    @IBOutlet var textField3: UITextField!
    @IBOutlet var textField4: UITextField!

    var hazards = ["a","b", "c"]
    var reasons = ["d", "e", "f"]
    var site = ["v","h","i","j"]
    var line = ["k", "l","m", "n"]

    override func viewDidLoad() {

        super.viewDidLoad()
        pickerView1 = UIPickerView()
        pickerView2 = UIPickerView()
        pickerView3 = UIPickerView()
        pickerView4 = UIPickerView()
        pickerView1.delegate = self
        pickerView2.delegate = self
        pickerView3.delegate = self
        pickerView4.delegate = self

        self.textField1.inputView = self.pickerView1;
        self.textField2.inputView = self.pickerView2;
        self.textField3.inputView = self.pickerView3;
        self.textField4.inputView = self.pickerView4;
    }

    func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int  {
        return 1
    }

    func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {

        if pickerView.tag == 0 {
            return hazards.count
        } else if pickerView.tag == 1 {
            return reasons.count
        } else if pickerView.tag == 2 {
            return  site.count
        } else if  pickerView.tag == 3 {
            return line.count
        }
        return 1
    }

    func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String! {

        if pickerView.tag == 0 {
            return hazards[row]
        } else if pickerView.tag == 1 {
            return reasons[row]
        } else if pickerView.tag == 2 {
            return site[row]
        } else if pickerView.tag == 3 {
            return line[row]
        }

        return ""
    }

    func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int)  {

        if pickerView.tag == 0 {
            textField1.text = hazards[row]
        } else if pickerView.tag == 1 {
            textField2.text = reasons[row]
        } else if pickerView.tag == 2 {
            textField3.text = site[row]
        } else if pickerView.tag == 3 {
            textField4.text = line[row]
        }
    }
}

Answer 1

您正在使用选择器视图'tag属性来确定哪个数组是给定选取器视图的数据源，但您最初没有设置标记。 tag默认为零，因此所有四个选择器视图都显示相同的数据。在实例化选择器视图后，添加以下内容：

pickerView1.tag = 0
pickerView2.tag = 1
pickerView3.tag = 2
pickerView4.tag = 3

具有多个文本字段输入视图的多个选择器视图Swift

1 个答案: