我决定在音频算法上使用C ++,更习惯于Matlab我有点挣扎。
第一步是使用sndfile库将wav文件记录到数组中。 我使用了库中的例子:
https://github.com/michaelwu/libsndfile/blob/master/examples/sfprocess.c
我想创建一个wavF类,其中包含wav的一般信息(采样频率,通道...)和wav文件的数据,以便进一步处理。
我几乎已经实现了这一点但是在wavfile.cpp中进入while ((readcount = sf_read_double (infile, data, BUFFER_LEN)))
循环(但并非总是)时发生了分段错误。我无法弄清楚原因。
我想使用带有缓冲区循环的类构造函数中的process_data函数将wav数据保存在数组double * m_wavData中。
这是他的代码:
主要:
#include <sndfile.h>
#include <stdio.h>
#include "wavfile.h"
int main (void)
{
SNDFILE *infile ;
const char *infilename = "Piano_mf_Gb2.wav" ;
SndfileHandle file;
file=SndfileHandle(infilename);
int test(initwav(infile, file, infilename));
if(test==1) return 0 ;
wavF wav1(infile, file, infilename);
sf_close (infile) ;
/* Close input and output files. */
return 0 ;
} /* main */
标题:
#ifndef WAVFILE_H_INCLUDED
#define WAVFILE_H_INCLUDED
#define BUFFER_LEN 1024
#include <sndfile.hh>
class wavF
{
public:
wavF(SNDFILE *infile, SndfileHandle file,const char * fName);
wavF(const unsigned int wavsize,const unsigned int channels,const unsigned int samplerate,const char * fileName);
~wavF();
protected:
const unsigned int m_wavsize;
const unsigned int m_channels;
const unsigned int m_samplerate;
const char * m_fileName;
double * m_wavData;
};
static void process_data (double *wavData, double * data, int count, int channels);
int initwav(SNDFILE *infile,SndfileHandle file,const char * fName);
#endif // WAVFILE_H_INCLUDED
和代码wavfile.cpp
#include "wavfile.h"
wavF::wavF(SNDFILE *infile, SndfileHandle file,const char * fName): m_channels(file.channels()),m_samplerate(file.samplerate()),m_wavsize(file.frames()),m_fileName(fName)
{
/* This is a buffer of double precision floating point values
** which will hold our data while we process it.
*/
static double data [BUFFER_LEN] ;
//initialise class array
double* m_wavData = new double[m_wavsize*m_channels] ;
printf ("Opened file '%s'\n", m_fileName) ;
printf ("Sample rate : %d\n", m_samplerate) ;
printf ("Channels : %d\n", m_channels) ;
printf ("Size : %d\n", m_wavsize) ;
puts ("") ;
//fill array with the wav channel
int readcount(0);
int counter(0);
while ((readcount = sf_read_double (infile, data, BUFFER_LEN)))
{
// printf("%i \n",counter);
// counter++;
process_data (m_wavData,data, readcount, m_channels) ;
} ;
/* RAII takes care of destroying SndfileHandle object. */
} /* read_file */
wavF::wavF(const unsigned int wavsize,const unsigned int channels,const unsigned int samplerate,const char * fileName):
m_channels(channels),m_samplerate(samplerate),m_wavsize(wavsize),m_fileName(fileName)
{
}
static void process_data (double *m_wavData,double *data, int count, int channels)
{
int k;
/* Process the data here.
** If the soundfile contains more then 1 channel you need to take care of
** the data interleaving youself.
*/
for (k = 0 ; k < channels*count ; k ++)
m_wavData [k] = data[k] ;
} /* process_data */
wavF::~wavF()
{
delete m_wavData;
printf("array is detroyed");
}
int initwav(SNDFILE *infile,SndfileHandle file, const char * fName)
{
SF_INFO sfinfo ;
if (! (infile = sf_open (fName, SFM_READ, &sfinfo)))
{ /* Open failed so print an error message. */
printf ("Not able to open input file %s.\n", fName) ;
puts (sf_strerror (NULL)) ;
return 1;
} ;
return 0;
}
我写了什么编码异端?有什么建议吗?
(在uiowa.edu数据库中找到音频wav) 谢谢。
答案 0 :(得分:1)
谢谢大家!
他们有几个错误:
1)正如Jean-FrançoisFabre所指出的,缓冲区大小不正确,导致尝试在数组<blockquote class="blockquote-reverse">
<p>Angular2 have a simplified functionality</p>
<footer>This is what we can<cite title="Source Title">Anirudha Das</cite></footer>
</blockquote>
中写入数据,从包含wav值m_wavData
的数组中取值。
---&GT; data
2)正如WhozCraig所指出的,我在类的构造函数中重新声明变量m_wavData = new double[m_wavsize*m_channels] ;
,导致隐藏同名的成员变量。 - &GT;删除了重新申报。
3)正如molbdnilo指出的那样,参数m_wavData
对我使用它的方式没有任何影响,导致不读取wav数据。
- &gt;通过在init和构造函数中打开来解决问题。
4)我一直在编写数组infile
的相同大小写(缓冲区的大小)。
- &GT;在好的案例中加入反写作。
这是我在更小版本(πάνταῥεῖ)中的解决方案:
m_wavData