Question

我有一个数据框：

                 cost       month  para
prod_code
040201060AAAIAI    43  2016-01-01  0402
040201060AAAIAJ    45  2016-02-01  0402
040201060AAAIAI    46  2016-03-01  0402
040201060AAAIAI    41  2016-01-01  0402
040201060AAAIAI    48  2016-02-01  0402

如何迭代行，并获取每个行的索引值？

d = { 'prod_code': ['040201060AAAIAI', '040201060AAAIAJ', '040201060AAAIAI', '040201060AAAIAI', '040201060AAAIAI', '040201060AAAIAI', '040301060AAAKAG', '040301060AAAKAK', '040301060AAAKAK', '040301060AAAKAX', '040301060AAAKAK', '040301060AAAKAK'], 'month': ['2016-01-01', '2016-02-01', '2016-03-01', '2016-01-01', '2016-02-01', '2016-03-01', '2016-01-01', '2016-02-01', '2016-03-01', '2016-01-01', '2016-02-01', '2016-03-01'], 'cost': [43, 45, 46, 41, 48, 59, 8, 9, 10, 12, 15, 13] }
df = pd.DataFrame.from_dict(d)
df.set_index('prod_code', inplace=True)

这就是我正在尝试的：

for i, row in df.iterrows():
    print row.index, row['cost']

但我明白了：

Index([u'items', u'cost'], dtype='object') 3.34461552621

更新：这与询问如何获取系列的索引名称相同，但措辞不同。此外，虽然答案与另一个问题相同，但问题却不一样！具体来说，这个问题将在人们谷歌为＆＃34; pandas指数行＆＃34;而不是＆＃34; pandas系列名称＆＃34;。

Answer 1

for i, row in df.iterrows():

为每个行Series返回Series，其中index名称是您正在迭代的行的d = { 'prod_code': ['040201060AAAIAI', '040201060AAAIAJ', '040201060AAAIAI', '040201060AAAIAI', '040201060AAAIAI', '040201060AAAIAI', '040301060AAAKAG', '040301060AAAKAK', '040301060AAAKAK', '040301060AAAKAX', '040301060AAAKAK', '040301060AAAKAK'], 'month': ['2016-01-01', '2016-02-01', '2016-03-01', '2016-01-01', '2016-02-01', '2016-03-01', '2016-01-01', '2016-02-01', '2016-03-01', '2016-01-01', '2016-02-01', '2016-03-01'], 'cost': [43, 45, 46, 41, 48, 59, 8, 9, 10, 12, 15, 13] } df = pd.DataFrame.from_dict(d) df.set_index('prod_code', inplace=True) for i, row in df.iterrows(): print row.name, row['cost'] 040201060AAAIAI 43 040201060AAAIAJ 45 040201060AAAIAI 46 040201060AAAIAI 41 040201060AAAIAI 48 040201060AAAIAI 59 040301060AAAKAG 8 040301060AAAKAK 9 040301060AAAKAK 10 040301060AAAKAX 12 040301060AAAKAK 15 040301060AAAKAK 13。你可以简单地做

import * as reduxFetchHelpers from 'redux-fetch-helpers';

您可以详细了解here

Answer 2

使用它迭代任何值df.ix[row_value,col_value]以查找列索引使用此函数

def find_column_number(column_name):
    x=list(df1.columns.values)
    print column_name
    col_lenth= len(x)
    counter=0
    count=[]
    while counter<col_lenth:
        if x[counter]==column_name:
            count=counter
        counter+=1
    return count

pandas：获取一行索引的值？

2 个答案: