Question

我正在尝试按住一个键并自动移动方块。我试图将pygame.key.get.pressed()更改为pygame.key.get.focused()，但仍然没有。

import pygame

pygame.init()
screen = pygame.display.set_mode((400,300))
pygame.display.set_caption("shield hacking")
JogoAtivo = True
GAME_BEGIN = False
# Speed in pixels per frame
x_speed = 0
y_speed = 0
cordX = 10
cordY = 100


def desenha():
    screen.fill((0, 0, 0))
    quadrado = pygame.draw.rect(screen, (255, 0, 0), (cordX, cordY ,50, 52))
    pygame.display.flip();    


while JogoAtivo:
    for evento in pygame.event.get():
        print(evento)
    #verifica se o evento que veio eh para fechar a janela
        pressed_keys = pygame.key.get_pressed()
        if evento.type == pygame.QUIT:
               JogoAtivo = False
               pygame.quit();
        if pressed_keys[pygame.K_SPACE]:
               print('GAME BEGIN')
               GAME_BEGIN = True
               desenha();        
        if pressed_keys[pygame.K_LEFT] and GAME_BEGIN:   
                   speedX=-3
                   cordX+=speedX
                   desenha()
        if pressed_keys[pygame.K_RIGHT] and GAME_BEGIN:
                   speedX=3
                   cordX+=speedX
                   desenha()

更新了代码，但仍存在同样的问题（包括KEYDOWN事件）。

import pygame

pygame.init()
screen = pygame.display.set_mode((400,300))
pygame.display.set_caption("shield hacking")
JogoAtivo = True
GAME_BEGIN = False
# Speed in pixels per frame
x_speed = 0
y_speed = 0
cordX = 10
cordY = 100


def desenha():
    screen.fill((0, 0, 0))
    quadrado = pygame.draw.rect(screen, (255, 0, 0), (cordX, cordY ,50, 52))
    pygame.display.flip();



while JogoAtivo:
    for evento in pygame.event.get():
        print(evento)
    #verifica se o evento que veio eh para fechar a janela
        if evento.type == pygame.QUIT:
               JogoAtivo = False
               pygame.quit();
        if evento.type == pygame.KEYDOWN:
            if evento.key == pygame.K_SPACE:
                   print('GAME BEGIN')
                   GAME_BEGIN = True
                   desenha();        
        if evento.type == pygame.KEYDOWN:
            if evento.key == pygame.K_LEFT:
                   speedX=-3
                   cordX+=speedX
                   desenha()
        if evento.type == pygame.KEYDOWN:
             if evento.key == pygame.K_RIGHT:
                   speedX=3
                   cordX+=speedX
                   desenha()

Answer 1

您无法在get_pressed()循环中使用for evento，因为当您按住键时，键不会生成事件，pygame.event.get()会返回空列表，因此for不执行任何操作

当您开始按键时，系统会生成单个偶数KEYDOWN，当您停止按键时，系统会生成单个偶数KEYUP，但系统不会在这两个时刻之间生成KEYDOW个事件（按住键时）。

您必须在get_pressed()循环后使用for（及其他代码）。

for evento in pygame.event.get():
    print(evento)
    if evento.type == pygame.QUIT:
          JogoAtivo = False
          pygame.quit();

# after for loop

pressed_keys = pygame.key.get_pressed()

if pressed_keys[pygame.K_SPACE]:
           print('GAME BEGIN')
           GAME_BEGIN = True
           desenha();        
if pressed_keys[pygame.K_LEFT] and GAME_BEGIN:   
               speedX=-3
               cordX+=speedX
               desenha()
if pressed_keys[pygame.K_RIGHT] and GAME_BEGIN:
               speedX=3
               cordX+=speedX
               desenha()

或（或多或少）

for evento in pygame.event.get():
    print(evento)
    #verifica se o evento que veio eh para fechar a janela
    if evento.type == pygame.QUIT:
           JogoAtivo = False
           pygame.quit();
    elif evento.type == pygame.KEYDOWN:
        if evento.key == pygame.K_SPACE:
               print('GAME BEGIN')
               GAME_BEGIN = True
        elif evento.key == pygame.K_LEFT:
               speedX = -3
        elif evento.key == pygame.K_RIGHT:
               speedX = 3
    elif evento.type == pygame.KEYUP:
        if evento.key in (pygame.K_LEFT, pygame.K_RIGHT):
               speedX = 0


# after loop

if GAME_BEGIN:
    cordX += speedX                   
    desenha()

Answer 2

根据我的理解（纠正我，如果我错了，我可能不太了解你的问题），但看起来你要做的就是按一下键，按住键，当你按住键时，让pygame不断处理KEYDOWN事件。在pygame中，这不起作用，但是可以以不同的方式处理按键。试想一下：如果你开始按住某个键，它会创建一个KEYDOWN事件。当您放开该键时，它会生成一个KEYUP事件。因此，在按下键之后按下键，然后按下。以下代码通过示例解释了该概念：

Rails.application.config.to_prepare do # to_prepare ensures that the monkey patching happens before the first request Devise::OmniauthCallbacksController.class_eval do # reopen the class def failure # redefine the failure method set_flash_message! :alert, :failure, kind: OmniAuth::Utils.camelize(failed_strategy.name), reason: failure_message redirect_to after_omniauth_failure_path_for(resource_name) end end end

我还没有能够测试代码（使用学校计算机），但是当你持有＆＃34; A＆＃34;键，每秒大约5次（这是一种限制fps的懒惰方式）。这同样适用于所有键，也适用于鼠标拖动。

Pygame按键移动一个Rect

2 个答案: