Question

我有一张表，其中有EMPID列。在此表中，我有多个具有相同EMPID的行。现在我想获得最后一行不同的EmpID。请查看下表数据。我希望得到带有ID为3,5和7的Row的所有列。

我想要结果如下：

我尝试使用以下查询，但是无效。

SELECT ID,
       EmpID,
       Salary,
       Leave,
       TakenLeave,
       field1,
       field2,
       field3
FROM   Table_2
GROUP  BY ID,
          EmpID,
          Salary,
          Leave,
          TakenLeave,
          field1,
          field2,
          field3

Answer 1

SELECT
TOP 1 WITH TIES 
ID, EmpID, Salary, Leave, TakenLeave, field1, field2, field3 
FROM [TABLE_NAME]
ORDER BY ROW_NUMBER() OVER(PARTITION BY EmpId ORDER BY Id DESC)

Answer 2

按EmpId提供row_number分区，并按Id desc排序。

<强>查询

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        }
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            document.getElementById("addToFav").innerText  = "Add to Favorites";
        }
    }
}

Answer 3

您可以使用此代码;

    select ID, EmpID, Salary, Leave, TakenLeave, field1, field2, field3
  from (select ID,
               EmpID,
               Salary,
               Leave,
               TakenLeave,
               field1,
               field2,
               field3 row_number() over(partition by EmpID order by id desc) as que
          from table_2)
 where que = 1

Answer 4

select * from myTable
where id in 
(
  select max(id) from myTable group by empId
);

Inner SQL选择每个empId的max（id），而外部select选择具有那些ID的行。

在sql中查找与EmpID不同的最后一条记录

4 个答案: