Question

这是我的数据

Id Name Amt

1  ABC  20
2  XYZ  30
3  ABC  25
4  PQR  50
5  XYZ  75
6  PQR  40

我想要每个特定名字的最后一条记录，如：

3  ABC  25
5  XYZ  75 
6  PQR  40

我尝试过分组，但我遗漏了一些东西。

SELECT     PatientID, Balance, PReceiptNo
FROM         tblPayment
GROUP BY PatientID, Balance, PReceiptNo

Answer 1

这样的事情应该有效：

SELECT p1.*
FROM tblPayment p1
LEFT JOIN tblPayment p2 ON p1.Name = p2.Name AND p1.Id < p2.Id
WHERE p2.Id IS NULL;

请参阅this SQLFiddle

Answer 2

应该类似于：

SELECT 
    id, 
    name, 
    amt
FROM
    myTable mt1
where mt1.id = (
                    SELECT 
                        MAX(id) 
                    FROM myTable mt2 
                    WHERE mt2.name = mt1.name
                )

Answer 3

这应该有效

select * from (select id, name,amount from test order by id desc)as t1 group by name;

fiddle

Answer 4

还有一个选择

SELECT *
FROM tblPayment p1
WHERE EXISTS (
              SELECT 1
              FROM tblPayment p2
              WHERE p1.Name = p2.Name
              HAVING MAX(p2.Id) = p1.Id
              )

请参阅SQLFiddle

上的演示

Answer 5

可能的解决方案：

Select p.* 
from tblPayment p
Inner join ( 
  Select name, max(id) as id
  From tblPayment 
  Group by name
) as latest on latest.id = p.id

找到Person的最后一条记录

5 个答案: