我正在尝试构建一个脚本,该脚本将从db表中下载用户,并根据其状态为每个用户附加一个新的随机IP。
问题是我写了很多代码,如果我继续使用这种方法,还有很多复制/粘贴工作要做。
有人能指出我如何正确地做到这一点的正确方向吗?
首先,我有50个这样的人:
$California_Text = file_get_contents('state/California.txt');
$California_textArray = explode("\n", $California_Text);
$Idaho_Text = file_get_contents('state/Idaho.txt');
$Idaho_textArray = explode("\n", $Idaho_Text);
$Illinois_Text = file_get_contents('state/Illinois.txt');
$Illinois_textArray = explode("\n", $Illinois_Text);
$Indiana_Text = file_get_contents('state/Illinois.txt');
$Indiana_textArray = explode("\n", $Indiana_Text);
$Iowa_Text = file_get_contents('state/Iowa.txt');
然后我有50个这样的人:
while($row = $result->fetch_assoc()) {
if (isset($row["state"])) {
foreach ($row as $value){
$California_randArrayIndexNum = array_rand($California_textArray);
$p_California = $California_textArray[$California_randArrayIndexNum];
$Texas_randArrayIndexNum = array_rand($Texas_textArray);
$p_Texas = $Texas_textArray[$Texas_randArrayIndexNum];
$Alabama_randArrayIndexNum = array_rand($Alabama_textArray);
$p_Alabama = $Alabama_textArray[$Alabama_randArrayIndexNum];
$Alaska_randArrayIndexNum = array_rand($Alaska_textArray);
$p_Alaska = $Texas_textArray[$Alaska_randArrayIndexNum];
$Arizona_randArrayIndexNum = array_rand($Arizona_textArray);
$p_Arizona = $California_textArray[$Arizona_randArrayIndexNum];
.....
然后我有50个这样的人:
if ($row["state"] == "california") {
$stateip = $p_California;
}
else if ($row["state"] == "texas") {
$stateip = $p_Texas;
}
else if ($row["state"] == "alabama") {
$stateip = $p_Alabama;
}
else if ($row["state"] == "alaska") {
$stateip = $p_Alaska;
}
我非常肯定这是一个糟糕的方法..也许有一种方法可以用3行foreach
做这一切?
答案 0 :(得分:1)
这样的事情:
// holds your content
$state_content = [];
while($row = $result->fetch_assoc()) {
// check do we have state set
if (!empty($row["state"])) {
$stateip = getStateIpByName($row["state"]);
}
}
/**
* Returns random IP
*/
function getStateIpByName($state_name) {
$content = getStateContent($state_name);
return $content[array_rand($content)];
}
/**
* Returns your's state content by state name
*/
function getStateContent($state_name) {
// checks do we already have content for this state
if(!isset($state_content[$state_name])) {
// generate file name
$file_name = "state/";
$file_name .= str_replace(" ", "", ucwords($state_name));
$file_name .= ".txt";
$state_text = file_get_contents($file_name);
$state_content[$state_name] = explode("\n", $state_text);
}
return $state_content[$state_name];
}
可能有一些错误,但你会明白。
答案 1 :(得分:0)
将所有状态存储在数组中,并在 $states=['california',..];
foreach($states as $state){
//Your code for one state
//Replace state name with $state variable
}
块中执行所有操作
<frutis>((?:(?!mango|grapes).)*)<\/frutis>