Question

如何将变量汽车与变量阵列相匹配？我需要将每个第一项（别克，梅赛德斯，雪佛兰）与我的琴弦相匹配。我这个案子应该记录别克和雪佛兰：

var car = "Buick, Chevrolet";
var array = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];


if (car = array) {
  console.log("Buick and Chevrolet matches.");  
};

但字符串可能不同 - 有时可能匹配项目0，有时可能是30，依此类推。

Answer 1

在现代Javascript中，您可以使用Set和.filter：

＆＃13;

var car = "Buick, Chevrolet";
var array = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];

var searchCars = new Set(car.match(/\w+/g));
var found = array.filter(([name]) => searchCars.has(name));

console.log(found);

＆＃13;

Answer 2

您可以拆分字符串并迭代每个元素并检查数组。

＆＃13;

var car = "Buick, Chevrolet",
    array = [["Buick", "2012", "USA", "1201"], ["Mercedes", "2005", "Germany", "12354"], ["Chevrolet", "1974", "USA", "9401"]],
    match = car.split(', ').every(function (a) {
        return array.some(function (b) { return a === b[0]; });
    });

console.log(match);

＆＃13;

var car = "Buick, Chevrolet",
    array = [["Buick", "2012", "USA", "1201"], ["Mercedes", "2005", "Germany", "12354"], ["Chevrolet", "1974", "USA", "9401"]],
    match = car.split(', ').every(function (a) {
        return array.some(function (b) { return a === b[0]; });
    });
if (match) {
    console.log(car.split(', ').join(' and ') + ' matches.');
}

＆＃13;

Answer 3

您可以reduce()使用indexOf()

检查元素

＆＃13;

var car = "Buick, Chevrolet";
var array = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];

var result = array.reduce(function(r, e, i) {
  if (car.indexOf(e[0]) != -1) {
    r.push(e[0]);
  }
  return r;
}, []).join(' and ') + ' matches.';

console.log(result)

＆＃13;

Answer 4

您可以在此使用Array.reduce

var car = "Buick, Chevrolet";
var array = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];


var matches = array.reduce(function(result, item){
  if(car.indexOf(item[0]) > -1) result.push(item);
  
  return result
}, []);

console.log(matches)

Answer 5

您必须循环数组，然后使用string.indexOf()

检查匹配

var car = "Buick, Chevrolet";
var array = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];
var matches = [];
var matchesStr = "";
array.forEach(function(item){
  if(car.indexOf(item[0]) > -1){
    matches.push(item[0]);
  }
});

if(matches.length > 0){
  var _last = matches.pop();
  matchesStr = matches.toString() + " and " + _last;
}
else{
  matchesStr = matches.toString()
}
console.log(matchesStr)

此外，如果您可以选择更新结构，那么最好使用对象数组而不是数组数组。

Answer 6

使用数组操作过滤器和贴图，您可以生成所需的过滤。首先过滤数组以仅获取与搜索条件匹配的元素。然后我映射它以仅提取进一步操作所需的数据。

var string = "Buick, Chevrolet";
var cars = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];

var findCars= function( arr, str ){
   return arr.filter(
         function(s){
              return str.indexOf(s[0])!==-1;
         }
    ).map(
       function(x){
         return x[0];
       }
    );
}

var res = findCars(cars, string);
console.log( res.join(" and ") + " matches.")

如果您以后需要整个匹配数据项，那么您应该跳过结果的映射，findCars方法将如下所示：

var findCars= function( arr, str ){
   return arr.filter(
         function(s){
              return str.indexOf(s[0])!==-1;
         }
    );
}

Answer 7

var car = "Buick, Chevrolet";
var array = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];

var result = car
              .split(', ')
              .reduce(
                (res, car) =>
                  (array.some(([arrayCar]) => car === arrayCar ? res.push(car) : null), res),
                []);

console.log(`${result.join(' and ')} matches`);

匹配字符串与多层数组

7 个答案: