Question

我正在使用Java，我需要您就如何为以下任务编写更好的代码发表意见。

我有以下字符串值

String testStr = "INCLUDES(ABC) EXCLUDES(ABC) EXCLUDES(ABC) INCLUDES(ABC) INCLUDES(ABC)"

我想操纵字符串并希望将所有INCLUDES语句合并为一个INCLUDES，结果应类似于以下内容：

INCLUDES(ABC,ABC, ABC) EXCLUDES(ABC, ABC)

Answer 1

我会使用这个类将初始字符串分解为新字符串： http://docs.oracle.com/javase/6/docs/api/java/util/StringTokenizer.html 并将它们放在一个数组中

启动一个新字符串，然后使用标记生成器分解括号内的部分（可以将其设置为使用（和）作为分隔符）并循环遍历数组并将它们连接成新字符串。

请注意，任何错误放置的空格（如INCLUDES（abc））都会搞砸了

Answer 2

这似乎是一种合理的方法：

使用testStr方法拆分StringUtils.split;使用“”或null作为令牌。
创建Map<String, List<String>>。我将其称为theMap
对于返回数组中的每个字符串，执行以下操作：
1. 使用“（）”作为标记拆分字符串。
2. 返回的数组应该有2个元素。第一个元素（索引0）是theMap的键，第二个元素（索引1）是要添加到列表中的值。

完成从拆分testStr返回的数组后，使用theMap中的键值构建一个新字符串，并将关联列表中的元素追加到字符串中。

Apache StringUtils

Answer 3

我为这个问题编写了一段代码，但我不知道它是否有用

根据您的格式，您可以使用“”拆分 testStr ，输出将如下所示： INCLUDES（ABC）
检查此字符串是否包含包含或排除
然后使用（）

像这样：

    String testStr = "INCLUDES(ABC) EXCLUDES(C) EXCLUDES(ABC) INCLUDES(AC) INCLUDES(AB)";
    String s[] = testStr.split(" ");
    String INCLUDES = "INCLUDES( ";
    String EXCLUDES = "EXCLUDES ( ";
    for (int i = 0; i < s.length; i++) {
        if (s[i].contains("INCLUDES")) {
            INCLUDES += (s[i].substring(s[i].indexOf("(") + 1, s[i].indexOf(")"))) + "  ";
        }

        else if (s[i].contains("EXCLUDES")) {
            EXCLUDES += (s[i].substring(s[i].indexOf("(") + 1, s[i].indexOf(")"))) + "  ";
        }
    }
    INCLUDES = INCLUDES + ")";
    EXCLUDES = EXCLUDES + ")";
    System.out.println(INCLUDES);
    System.out.println(EXCLUDES);

Answer 4

我已将小实用程序结果记下来如下

if text = "EXCLUDES(ABC) EXCLUDES(ABC) INCLUDES(BMG) INCLUDES(EFG) INCLUDES(IJK)";

output = EXCLUDES(ABC) EXCLUDES(ABC) INCLUDES(BMG & EFG & IJK)

以下是我的java代码，请看一下，如果有任何人可以改进它，请随意。

import java.util.ArrayList;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

import com.sun.xml.internal.ws.util.StringUtils;

/**
 * Created by IntelliJ IDEA.
 * User: fkhan
 * Date: Aug 31, 2012
 * Time: 1:36:45 PM
 * To change this template use File | Settings | File Templates.
 */


public class TestClass {


    public static void main(String args[]) throws Exception {

        //String text = "INCLUDES(ABC) EXCLUDES(ABC) EXCLUDES(ABC) INCLUDES(EFG) INCLUDES(IJK)";
        String text = "EXCLUDES(ABC) EXCLUDES(ABC) INCLUDES(BMG) INCLUDES(EFG) INCLUDES(IJK)";
        List<String> matchedList = findMatchPhrase("INCLUDES", text);
        String query = combinePhrase(text, "INCLUDES", matchedList);
        System.out.println(query);


    }

    /**
     * This method takes query combine and & multiple phrases
     * @param expression
     * @param keyword
     * @param matchedItemList
     * @return
     */
    private static String combinePhrase(String expression, String keyword, List<String> matchedItemList) {

        //if only one phrase found return value
        if(matchedItemList.isEmpty() || matchedItemList.size() ==1){
            return expression;
        }

        //do not remove first match
        String matchedItem = null;
        for (int index = 1; index < matchedItemList.size(); index++) {

            matchedItem = matchedItemList.get(index);

            //remove match items from string other then first match
            expression = expression.replace(matchedItem, "");
        }

        StringBuffer textBuffer = new StringBuffer(expression);

        //combine other matched strings in first matched item
        StringBuffer combineStrBuf = new StringBuffer();
        if (matchedItemList.size() > 1) {

            for (int index = 1; index < matchedItemList.size(); index++) {
                String str = matchedItemList.get(index);
                combineStrBuf.append((parseValue(keyword, str)));
                combineStrBuf.append(" & ");

            }
            combineStrBuf.delete(combineStrBuf.lastIndexOf(" & "), combineStrBuf.length());
        }

        // Inject created phrase into first phrase
        //append in existing phrase
        return injectInPhrase(keyword, textBuffer, combineStrBuf.toString());
    }

    /**
     *
     * @param keyword
     * @param textBuffer
     * @param injectStr
     */
    private static String injectInPhrase(String keyword, StringBuffer textBuffer, String injectStr) {
        Matcher matcher = getMatcher(textBuffer.toString());
        while (matcher.find()) {

            String subStr = matcher.group();
            if (subStr.startsWith(keyword)) {
                textBuffer.insert(matcher.end()-1, " & ".concat(injectStr));
                break;
            }

        }

       return textBuffer.toString();
    }

    /**
     * @param expression
     * @param keyword
     * @return
     */
    private static String parseValue(String keyword, String expression) {

        String parsStr = "";
        if (expression.indexOf(keyword) > -1) {
            parsStr = expression.replace(keyword, "").replace("(", "").replace(")", "");
        }

        return parsStr;
    }


    /**
     * This method creates matcher object
     * and return for further processing
     * @param expression
     * @return
     */
    private static Matcher getMatcher(String expression){
        String patternString = "(\\w+)\\((.*?)\\)";
        Pattern pattern = Pattern.compile(patternString);
        return pattern.matcher(expression);
    }
    /**
     * This method find find matched items by keyword
     * and return as list
     * @param keyword
     * @param expression
     * @return
     */
    private static List<String> findMatchPhrase(String keyword, String expression) {
        List<String> matchList = new ArrayList<String>(3);

        keyword = StringUtils.capitalize(keyword);
        Matcher matcher = getMatcher(expression);

        while (matcher.find()) {

            String subStr = matcher.group();
            if (subStr.startsWith(keyword)) {
                matchList.add(subStr);
            }
        }

        return matchList;
    }



}

Java字符串匹配表达式String Array

4 个答案: