我有表格和jquery。我将通过ajax提交表格。
$("form#form").submit(function (event) { //submit nama pihak vendor
event.preventDefault();
var formData = new FormData($(this)[0]);
//validation in here if duplicate
$.ajax({
url: 'vendor_inout/vendor_inout_crud.php', //case:"insert_barang_in"
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function (data) {
console.log(data);
if(data == 0){
alert('failed');
}else{
alert("success");
}
}
});
return false;
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<body>
<form id='form'>
<select name='model[]'>
<option value=''></option>
<option value='model-a'>model-a</option>
<option value='model-b'>model-b</option>
<option value='model-c'>model-c</option>
</select>
<br>
<select name='model[]'>
<option value=''></option>
<option value='model-a'>model-a</option>
<option value='model-b'>model-b</option>
<option value='model-c'>model-c</option>
</select>
<br>
<input type='submit' value='submit'>
</form
</body>
&#13;
如果name='model[]'
的值相同,如何在将数据提交到file.php之前显示警报?警报必须在标记//validation in here if duplicate
中。
答案 0 :(得分:1)
试试这个:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<body>
<form id='form'>
<select name='model[]' id='model1'>
<option value=''></option>
<option value='model-a'>model-a</option>
<option value='model-b'>model-b</option>
<option value='model-c'>model-c</option>
</select>
<br>
<select name='model[]' id="model2">
<option value=''></option>
<option value='model-a'>model-a</option>
<option value='model-b'>model-b</option>
<option value='model-c'>model-c</option>
</select>
<br>
<input type='submit' value='submit'>
</form>
</body>
$("form#form").submit(function (event) { //submit nama pihak vendor
var formData = new FormData($(this)[0]);
event.preventDefault();
var model1 = $("#model1").val();
var model2 = $("#model2").val();
//validation in here if duplicate
var flag = 0;
if (model1 == model2) { flag++; }
if (flag > 0) {
alert("Duplicate");
} else {
$.ajax({
url: 'vendor_inout/vendor_inout_crud.php', //case:"insert_barang_in"
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function (data) {
console.log(data);
if(data == 0){
alert('failed');
}else{
alert("success");
}
}
});
}
return false;
});
答案 1 :(得分:0)
尝试一次
$("form#form").submit(function (event) { //submit nama pihak vendor
event.preventDefault();
var formData = new FormData($(this)[0]);
//validation in here if duplicate
$.ajax({
url: 'vendor_inout/vendor_inout_crud.php', //case:"insert_barang_in"
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function (data) {
console.log(data);
if(data == 0){
alert('failed');
}else{
alert("success");
}
}
});
alert('Before');
return false;
;
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<body>
<form id='form'>
<select name='model[]'>
<option value=''></option>
<option value='model-a'>model-a</option>
<option value='model-b'>model-b</option>
<option value='model-c'>model-c</option>
</select>
<br>
<select name='model[]'>
<option value=''></option>
<option value='model-a'>model-a</option>
<option value='model-b'>model-b</option>
<option value='model-c'>model-c</option>
</select>
<br>
<input type='submit' value='submit'>
</form
</body>
答案 2 :(得分:0)
根据您对@Samudrala Ramu的评论回答:请使用以下代码。
如果所有组合框中的值相同isAllSame
函数将返回true,否则它将返回false。
function isAllSame()
{
var model=document.getElementsByName("model[]");
for(var i = 1; i < model.length; i++)
{
if(model[i].value !== model[0].value)
return false;
}
return true;
}
$("form#form").submit(function (event) { //submit nama pihak vendor
event.preventDefault();
var formData = new FormData($(this)[0]);
if(isAllSame())
{
alert(" All Selected value are same");
return false;
}
//validation in here if duplicate
$.ajax({
url: 'vendor_inout/vendor_inout_crud.php', //case:"insert_barang_in"
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function (data) {
console.log(data);
if(data == 0){
alert('failed');
}else{
alert("success");
}
}
});
return false;
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id='form'>
<select name='model[]'>
<option value=''></option>
<option value='model-a'>model-a</option>
<option value='model-b'>model-b</option>
<option value='model-c'>model-c</option>
</select>
<br>
<select name='model[]'>
<option value=''></option>
<option value='model-a'>model-a</option>
<option value='model-b'>model-b</option>
<option value='model-c'>model-c</option>
</select>
<br>
<input type='submit' value='submit'>
</form>