当数据插入数据库时,我想显示一个alert
。这是将请求发送到EditDeleteLecture.php
的ajax代码。但是主要的问题是,插入数据时,它在alert
中显示了Network pane
。
Ajax代码就是
function addRecord() {
var formData = new FormData($("#form1")[0]); //It automatically collects all fields from form
$.ajax({
url: "ajax/EditDeleteLecture.php",
type: "post",
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function(output) {
readRecords();
$('#form1').trigger("reset");
}
});
}
这是EditDeleteLecture.php
页面,它将数据插入数据库。
if (isset($_FILES['files']['name'])) {
$files = $_FILES['files']['name'];
$desc = $_POST['description'];
$subject = $_POST['subject'];
$path = 'Lectures/'.$files;
move_uploaded_file($_FILES["files"]["tmp_name"], $path);
$date = date('d-M-y');
$query = "INSERT INTO content(file_name,course_code,description,file_path,upload_date) VALUES ('$files','$subject','$desc','$path','$date')";
$cm = sqlsrv_query($conn, $query);
if ($cm) {
echo '<script>alert("data Inserted Successfully");</script>';
}
}
答案 0 :(得分:1)
在ajax成功响应中编写警报,例如
function addRecord() {
var formData = new FormData($("#form1")[0]); //It automatically collects all fields from form
$.ajax({
url: "ajax/EditDeleteLecture.php",
type: "post",
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function(output) {
alert("record inserted successfully.")
alert(output);
readRecords();
$('#form1').trigger("reset");
}
});
}
答案 1 :(得分:0)
警告ajax响应
使用以下代码更新您的php代码
if (isset($_FILES['files']['name'])) {
$files = $_FILES['files']['name'];
$desc = $_POST['description'];
$subject = $_POST['subject'];
$path = 'Lectures/'.$files;
move_uploaded_file($_FILES["files"]["tmp_name"], $path);
$date = date('d-M-y');
$query = "INSERT INTO content(file_name,course_code,description,file_path,upload_date) VALUES ('$files','$subject','$desc','$path','$date')";
$cm = sqlsrv_query($conn, $query);
if ($cm) {
$result['status']="Succsess";
$result['message']="Record Inserted Successfully";
}else{
$result['status']="failed";
$result['message']="Somethink Went Wrong";
}
echo json_encode($result);
}
检查您的Ajax代码状态
function addRecord() {
var formData = new FormData($("#form1")[0]); //It automatically collects all fields from form
$.ajax({
url: "ajax/EditDeleteLecture.php",
type: "post",
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function(output) {
var json = $.parseJSON(output);
if(json.status == "Succsess"){
readRecords();
$('#form1').trigger("reset");
alert(json.message);
}else{
alert(json.message);
}
}
});
}