Question

我想要检索mysql结果，但我的查询不起作用，因为我是新的计算机编程或计算机数据库。

SELECT guid, post_name
FROM `wp_posts`
WHERE `post_parent` = 0 and `post_type` = 'post' and post_title != 'Auto Draft'

返回：

guid                    post_name   
http://localhost/?p=21  post-2-title
http://localhost/?p=12  post-4-title

和

SELECT guid as children_url, post_parent as post_parent
FROM `wp_posts`
WHERE `post_parent` != 0 and `post_type` = 'attachment' and post_title != 'Auto Draft'

返回：

children_url                               post_parent  
http://localhost/attachment-post-1            12
http://localhost/attachment-post-2            12
http://localhost/attachment-post-3            12
http://localhost/attachment-post-4            12
http://localhost/attachment-post-5            12
http://localhost/attachment-post-6            12
http://localhost/attachment-post-7            12
http://localhost/attachment-post-8            12
http://localhost/attachment-post-9            21
http://localhost/attachment-post-10           21
http://localhost/attachment-post-11           21
http://localhost/attachment-post-12           21
http://localhost/attachment-post-13           21
http://localhost/attachment-post-14           21
http://localhost/attachment-post-15           21
http://localhost/attachment-post-16           21

我尝试过多次查询，但没有成功，

SELECT guid as children_url, post_parent as post_parent
FROM `wp_posts`
WHERE `post_parent` != 0 and `post_type` = 'attachment' and post_title != 'Auto Draft'
  and SELECT guid, post_name FROM `wp_posts`
      WHERE `post_parent` = 0 and `post_type` = 'post' and post_title != 'Auto Draft'

引发错误：

1064 - 您的SQL语法出错;检查手册对应于您的MySQL服务器版本，以便使用正确的语法 'SELECT guid附近，post_name FROM wp_posts WHERE post_parent = 0 和post_type ='在第1行

我想要的结果如下：

 children_url                              post_parent              post_paraent_guid       post_parent_title
http://localhost/attachment-post-1            12                    http://localhost/?p=12  post-2-title
http://localhost/attachment-post-2            12                    http://localhost/?p=12  post-2-title
http://localhost/attachment-post-3            12                    http://localhost/?p=12  post-2-title
http://localhost/attachment-post-4            12                    http://localhost/?p=12  post-2-title
http://localhost/attachment-post-5            12                    http://localhost/?p=12  post-2-title
http://localhost/attachment-post-6            12                    http://localhost/?p=12  post-2-title
http://localhost/attachment-post-7            12                    http://localhost/?p=12  post-2-title
http://localhost/attachment-post-8            12                    http://localhost/?p=12  post-2-title
http://localhost/attachment-post-9            21                    http://localhost/?p=21  post-4-title
http://localhost/attachment-post-10           21                    http://localhost/?p=21  post-4-title
http://localhost/attachment-post-11           21                    http://localhost/?p=21  post-4-title
http://localhost/attachment-post-12           21                    http://localhost/?p=21  post-4-title
http://localhost/attachment-post-13           21                    http://localhost/?p=21  post-4-title
http://localhost/attachment-post-14           21                    http://localhost/?p=21  post-4-title
http://localhost/attachment-post-15           21                    http://localhost/?p=21  post-4-title
http://localhost/attachment-post-16           21                    http://localhost/?p=21  post-4-title

任何帮助都会表示赞赏。

谢谢

Answer 1

试试这个

SELECT
    pc.guid as children_url,
    pc.post_parent as post_parent,
    pp.guid as post_paraent_guid,
    pp.post_title as post_parent_title
FROM
    wp_posts pc
    left join wp_posts pp on pp.ID=pc.post_parent
WHERE
    pc.post_type = 'attachment'
    and pc.post_title != 'Auto Draft'
ORDER BY
    pc.guid

何时加入或连接mysql时出现语法错误

1 个答案: