Question

public function getIncomeBranches()
{   
    return
    $this->db->select('t1.subject_name, t2.payment_grand, t2,.payment_date, t3.level_id')
                     ->join('groups AS t3', 't1.subject_id = t3.group_id', 'left')
                     ->join('payments AS t2', 't1.subject_id = t2.payment_id')
                     ->group_by('t1.subject_id')
                     ->get("subjects AS t1")->result();
}

问题

错误号码：1064

您的SQL语法有错误;检查手册   对应于您的MySQL服务器版本，以便使用正确的语法   靠近＆＃39; t3。level_id FROM subjects AS t1 LEFT JOIN groups AS   t3 ON t1。“sub＆＃39;在第1行

SELECT `t1`.`subject_name`, `t2`.`payment_grand`, `t2`, .`payment_date`, `t3`.`level_id` FROM `subjects` AS `t1` LEFT JOIN `groups` AS `t3` ON `t1`.`subject_id` = `t3`.`group_id` JOIN `payments` AS `t2` ON `t1`.`subject_id` = `t2`.`payment_id` GROUP BY `t1`.`subject_id`

文件名：   d：/www/domains/uzdev/taraqqiyot/application/models/Dashboard_model.php

行号：69

我想通过ID来记录主题并显示该主题的所有付款。

Answer 1

查询,中的不受欢迎的t2,.payment_date,只是将其从第一行删除

这将是

$this->db->select('t1.subject_name, t2.payment_grand, t2.payment_date, t3.level_id')
->join('groups AS t3', 't1.subject_id = t3.group_id', 'left')
                     ->join('payments AS t2', 't1.subject_id = t2.payment_id')
                     ->group_by('t1.subject_id')
                     ->get("subjects AS t1")->result();

Answer 2

你的错误 - ＆gt; t2,.payment_date,

public function getIncomeBranches()
{   
    return
    $this->db->select('t1.subject_name, t2.payment_grand, t2.payment_date, t3.level_id')
                     ->join('groups AS t3', 't1.subject_id = t3.group_id', 'left')
                     ->join('payments AS t2', 't1.subject_id = t2.payment_id')
                     ->group_by('t1.subject_id')
                     ->get("subjects AS t1")->result();
}

Answer 3

t2,.payment_date至t2.payment_date以及

$this->db->select('t1.subject_name, t2.payment_grand, t2.payment_date, t3.level_id')
    ->join('groups AS t3', 't1.subject_id = t3.group_id', 'left')
    ->join('payments AS t2', 't1.subject_id = t2.payment_id')
    ->group_by('t1.subject_id')
    ->get("subjects AS t1")->result();

加入时，语法就是这个，

 $this->db->join("table1","table1.id = table2.id");

如果正确，请检查第二次加入。

加入 - 语法错误

问题

3 个答案: