Question

所以我试图在我的工作产品（三角形制造商）中添加一些代码，如果程序允许的话，你可以在三角形的中间添加一些文字。到目前为止，我已经添加了正确数量的x和缩进的文本，但程序仍然输出x的原始中间行。例如，Triangle（3，＆＃34; M＆＃34;）将输出

   x
  xxx
  xMx
 xxxxx

而不是

   x
  xMx
 xxxxx

这就是我想要的。我尝试在x == textrow - 1时使用break但是这似乎不起作用我觉得我要做的就是以某种方式打破循环，用x＆＃39跳过用户的文本跳过计算机通常会打印xxx并继续运行的部分。但我不知道该怎么做。这是我的代码，唯一真正相关的部分是＆＃34;如果x＆gt; 1＆＃34; （我知道这可能是你见过的效率最低的东西，但我是初学者，我会按照我的理解行事。）

def Triangle(height, text):
    text1 = str(text)
    number_of_x2 = (height - len(text)) / 2


    if height % 2 == 0:
        print "Please enter a height that is odd"

    else:
        stringTriangle = "x"
        HT = ""

        for x in range(height + height - 1):
            HT += "x"
            length_of_HT = len(HT)
            length_of_HT = int(length_of_HT)

        length_of_HT = len(HT) / 2 
        length_of_HT = int(length_of_HT)
        indent_text_length = length_of_HT / 2
        for x in range(height): #should be height change later
            if x == 1:
                stringTriangle = " " * length_of_HT + stringTriangle
                print stringTriangle


            if x > 1:
                textrow = height / 2


                for x in range(height): 
                    if stringTriangle == HT:
                        break


                    if len(text) == len(stringTriangle):
                        break


                    if x == textrow:

                        text = ""
                        text = " " * number_of_x2

                        for x in range(number_of_x2):
                            text+="x"

                        text = text + text1

                        for x in range(number_of_x2):
                            text+="x"

                        print text


                    stringTriangle += "xx"
                    stringTriangle = stringTriangle[1:]
                    print stringTriangle

谢谢！

Answer 1

我不确定你的代码是如何工作的，但是我调整了它直到它返回了我预期的结果。此外，我对有点难看的部分做了一些小改动。这应该做你想要的：

def Triangle(height, text):
number_of_x2 = (height - len(text)) / 2

if not height % 2:
    print "Please enter a height that is odd"

else:
    string_triangle = "x"
    ht = "x" * (2 * height - 1)

    length_of_ht = len(ht) / 2 
    indent_text_length = length_of_ht / 2
    text_row = height / 2

    # should be height change later
    for x in range(height):
        if x == 1:
            string_triangle = " " * length_of_ht + string_triangle
            print string_triangle

        if x > 1:
            for x in range(height):
                if x == text_row - 1:
                    string_triangle += "xx"
                    string_triangle = string_triangle[1:]
                    continue

                if x == textrow:
                    special_line = " " * (number_of_x2 + len(text) / 2) + "x" * number_of_x2 + text + "x" * number_of_x2

                    if not len(text) % 2:
                        special_line += "x"

                    print special_line

                if string_triangle == ht or len(text) == len(string_triangle):
                    break

                string_triangle += "xx"
                string_triangle = string_triangle[1:]

                print string_triangle

在Python中，是否可以跳过for循环的某个部分？

1 个答案: