Question

我做了一个猜数游戏，如果你愿意的话，我已经让它重新开始了。然而，它重新开始，回到开始并再次询问“myname”，我怎么能这样做，以便它回到它想到一个数字的位，并从第一次记住我的名字？

import random
restart = '1'
def main():
    guessestaken = 0

    print ('Hello, what is your name?')
    myname = raw_input()


    number = random.randint(1, 50)
    print ('Okay ' + myname + ', I am thinking of a number between 1 and 50. You have 5 guesses.')

    while guessestaken < 5:
        print ('Take a guess.')
        guess = input()
        guess = int(guess)

        guessestaken = guessestaken + 1

        if guess < number:
            print ('Your guess is too low.')

        if guess > number:
            print ('Your guess is too high.')

        if guess == number:
            break

    if guess == number:
        guessestaken = str(guessestaken)
        print ('Good job ' + myname + ', you got the correct answer in ' + guessestaken + ' guesses')


    if guess != number:
        number = str(number)
        print ('Oh dear ' + myname + ', the number I was thinking of was ' + number + '.')

while restart == '1':
    main()
    restart = raw_input('Would you like to try again? Press 1 for Yes, and 2 for No: ')

此刻它再次要求我的名字。我的意思是，它很实用，很讨厌。

由于

Answer 1

你可以简单地移动

print ('Hello, what is your name?')
myname = raw_input()

在main()函数之前，因此它只会运行一次。

您还需要在raw_input()函数中使用input()代替main()。

Answer 2

最简单的方法是在main()函数之外询问名称，然后将其传递给每个游戏。从技术上讲，你不必传入它（python仍然可以访问变量），但最好这样做。

def main(myname):
    # Remove the name prompt from here

...

print ('Hello, what is your name?')
myname = raw_input()

while restart == '1':
    main(myname)
    restart = raw_input('Would you like to try again? Press 1 for Yes, and 2 for No: ')

Answer 3

一个简单的解决方法是将myname放在main之外，将myname = ''放在restart = '1'之下。然后，只询问玩家姓名，如果他的名字不明，即：

if myname == '':
    print ('Hello, what is your name?')
    myname = raw_input()

转到while循环的某个部分

3 个答案: