我使用OpenCV和v4l2loopback库来模拟视频设备:
modprobe v4l2loopback devices=2
然后我检查一下我的设备:
root@blah:~$ v4l2-ctl --list-devices
Dummy video device (0x0000) (platform:v4l2loopback-000):
/dev/video1
Dummy video device (0x0001) (platform:v4l2loopback-001):
/dev/video2
XI100DUSB-SDI (usb-0000:00:14.0-9):
/dev/video0
video0是我的实际相机,我从中获取帧,然后我打算通过OpenCV处理它们并将其写入video2(我相信这是一个接收器)。
以下是我尝试这样做的方法:
int width = 320;
int height = 240;
Mat frame(height, width, CVX_8UC3, Scalar(0, 0, 255));
cvtColor(frame, frame, CVX_BGR2YUV);
int fourcc = CVX_FOURCC('Y', 'U', 'Y', '2');
cout << "Trying to open video for write: " << FLAGS_out_video << endl;
VideoWriter outputVideo = VideoWriter(
FLAGS_out_video, fourcc, 30, frame.size());
if (!outputVideo.isOpened()) {
cerr << "Could not open the output video for write: " << FLAGS_out_video
<< endl;
}
据我所知,视频输出格式应为YUYV
(在OpenCV中等于YUY2
)。如果我错了,请纠正我。在我的代码中,我还没有写入outputVideo
任何内容,只是尝试打开它进行写入,但由于某种原因我不断获得outputVideo.isOpened()==false
,输出中没有其他错误/信息:< / p>
root@blah:~$ main --uid='' --in_video='0' --out_video='/dev/video2'
Trying to open video for write: /dev/video2
Could not open the output video for write: /dev/video2
我很感激有关如何调试/解决此问题的任何建议或帮助。提前谢谢!