Question

假设我有下表：

User_ID Activity_ID
123     222
123     333
124     222
124     224
124     333
125     224
125     333

我想通过重叠的不同组合返回计数用户，例如：

Activity_ID_1 Activity_ID_2 Count_of_Users
222           333           2 
222           224           2

在上面的示例中，有2个用户同时完成了223 AND 333。

我不想手动定义每个组合，因为我正在使用93个不同的activity_ids。有没有办法在Oracle SQL中完全执行此操作？

Answer 1

假设您有一个带有活动ID的activity表，并且您只想计算具有相同两个活动的DISTINCT用户（同时具有两次活动的用户将不计算）：

select a1.activity_id, a2.activity_id, count(distinct f.user_id)
from   activity a1 inner join facts    f  on a1.activity_id = f.activity_id
                   inner join activity a2 on a2.activity_id = f.activity_id
where  a1.activity_id < a2.activity_id
group by a1.activity_id, a2.activity_id
having count(distinct f.user_id) >= 2
;

facts是您的事实表的名称（您在问题中显示的名称）。

编辑：如果facts表（或视图或子查询或其他）已经被user_id“区分”了，那么从我的解决方案中删除“distinct”;这将使其更有效率。注意：“distinct”出现两次，一次出现在SELECT中，再出现在HAVING中。

Answer 2

Oracle安装程序：

CREATE TABLE data ( User_ID, Activity_ID ) AS
SELECT 123, 222 FROM DUAL UNION ALL
SELECT 123, 333 FROM DUAL UNION ALL
SELECT 124, 222 FROM DUAL UNION ALL
SELECT 124, 224 FROM DUAL UNION ALL
SELECT 124, 333 FROM DUAL UNION ALL
SELECT 125, 224 FROM DUAL UNION ALL
SELECT 125, 333 FROM DUAL;

CREATE TYPE INTLIST AS TABLE OF INT;
/

<强>查询：

WITH Activities ( User_IDs, Activity_ID ) AS (
  SELECT CAST( COLLECT( User_ID ) AS INTLIST ),
         Activity_ID
  FROM   data
  GROUP BY Activity_ID
)
SELECT a.Activity_ID,
       b.Activity_ID,
       CARDINALITY( a.User_IDs MULTISET INTERSECT b.User_IDs ) AS "Count"
FROM   Activities a
       INNER JOIN
       Activities b
       ON ( CARDINALITY( a.User_IDs MULTISET INTERSECT b.User_IDs ) > 1
           AND a.Activity_ID < b.Activity_ID );

<强>输出：

ACTIVITY_ID ACTIVITY_ID      Count
----------- ----------- ----------
        222         333          2 
        224         333          2

Oracle：如何在行中查找重叠

2 个答案: