Question

我正在使用T-SQL

我有一个表：带有平台源的用户会话。

我需要获得仅使用“Android”和“桌面”的用户。

数据示例：

ID | Source  | DateTime
 1 | Android | 2016-06-01
 1 | Desktop | 2016-06-01
 2 | Android | 2016-06-02
 3 | iOS     | 2016-06-01
 3 | Desktop | 2016-06-02
 3 | Android | 2016-06-03

预期结果：

ID = 1

ID = 2是错误的，因为它只有“Android”
ID = 3是错误的，因为它有“IOS”

Answer 1

我称之为set-within-sets查询。我喜欢使用group by和having来解决此问题，因为这是表达这些条件的非常灵活的方法：

select id
from t
group by id
having sum(case when source = 'Android' then 1 else 0 end) > 0 and -- has Android
       sum(case when source = 'Desktop' then 1 else 0 end) > 0 and -- has Desktop
       sum(case when source not in ('Android', 'Desktop') then 1 else 0 end) = 0 -- has nothing else

Answer 2

试试这个：

SELECT Id 
FROM mytable
GROUP BY Id
HAVING COUNT(*) = COUNT(CASE WHEN Source='Android' THEN 1 END) + 
                  COUNT(CASE WHEN Source='Desktop' THEN 1 END) AND
       COUNT(CASE WHEN Source='Desktop' THEN 1 END) > 0 AND
       COUNT(CASE WHEN Source='Android' THEN 1 END) > 0

Answer 3

试试这个

select id from your_table
group by id
having 
max(case when source in ('Android') then 1 else 0 end))=1
and
max(case when source in ('Desktop') then 1 else 0 end))=1
and count(distinct source)=2

Answer 4

尝试使用

Select * 
from yourtable a 
where a.source = 'Android' 
  and not exist (Select b.id 
                 from yourtable b 
                 where b.id = a.id and b.source <> 'Android')

选择仅包含许多

4 个答案: