Question

我有一类名为“EpisodeInfoData”的属性

class EpisodeInfoData {
    var episodeId = ""
    var episodeName = ""
}

我将这些类的对象存储到一个字典中，其第一个元素是“String”，另一个元素是“EpisodeInfoData”类对象的数组

var episodes    = Dictionary<String, [EpisodeInfoData]>()

let infoObj1 = EpisodeInfoData()
infoObj1.episodeId           = "1"
infoObj1.episodeName         = "one"

let infoObj2 = EpisodeInfoData()
infoObj2.episodeId           = "2"
infoObj2.episodeName         = "two"

let infoObj3 = EpisodeInfoData()
infoObj3.episodeId           = "3"
infoObj3.episodeName         = "three"

let infoObj4 = EpisodeInfoData()
infoObj4.episodeId           = "4"
infoObj4.episodeName         = "four"

let infoObj5 = EpisodeInfoData()
infoObj5.episodeId           = "5"
infoObj5.episodeName         = "five"

let infoObj6 = EpisodeInfoData()
infoObj6.episodeId           = "6"
infoObj6.episodeName         = "six"

let infoObj7 = EpisodeInfoData()
infoObj7.episodeId           = "7"
infoObj7.episodeName         = "seven"

let infoObj8 = EpisodeInfoData()
infoObj8.episodeId           = "8"
infoObj8.episodeName         = "eight"

episodes["season1"] = [infoObj1,infoObj2,infoObj3,infoObj4]
episodes["season2"] = [infoObj5,infoObj6,infoObj7,infoObj8]

我希望在“剧集”词典中获得季节名称，其剧集名称为“8”。我试着在它上面应用过滤器它没有用。

任何人都可以建议我使用过滤器查找结果而不使用过滤器。

提前谢谢

Answer 1

不得不添加另一个答案，感谢那些在没有真正帮助的情况下投票的人。

试试这个

if let episode = (episodes.filter { $0.1.contains { $0.episodeName == "eight" } }).first {
    print(episode.0) // season2
}

Answer 2

这是working solution。

struct EpisodeInfoData {
    let episodeId: String
    let episodeName: String
}

let episodes = [
    "season1": [
        EpisodeInfoData(
            episodeId: "1",
            episodeName: "one"
        ),
        EpisodeInfoData(
            episodeId: "2",
            episodeName: "two"
        ),
        EpisodeInfoData(
            episodeId: "3",
            episodeName: "three"
        ),
        EpisodeInfoData(
            episodeId: "4",
            episodeName: "four"
        ),
    ],

    "season2": [
        EpisodeInfoData(
            episodeId: "5",
            episodeName: "five"
        ),
        EpisodeInfoData(
            episodeId: "6",
            episodeName: "six"
        ),
        EpisodeInfoData(
            episodeId: "7",
            episodeName: "seven"
        ),
        EpisodeInfoData(
            episodeId: "8",
            episodeName: "eight"
        )
    ]
]

let desiredName = "eight"

let result = episodes.filter{ _, seasonEpisodes in
    return seasonEpisodes.contains{ $0.episodeName == desiredName }
}.map{ key, value in return key}

print(result)

首先过滤剧集字典。仅当值（seasonEpisodes数组）包含具有desiredName的剧集时，才会保留字典中的键值对。然后，映射这些键值对，并仅返回键（季节名称）。

在对象数组的字典中应用过滤器

2 个答案: