Question

我有一些数据模仿这样的api调用：

 var people:Array<Dictionary<String, AnyObject>> = [
     ["name":"harry", "age": 28, "employed": true, "married": true],
     ["name":"larry", "age": 19, "employed": true, "married": true],
     ["name":"rachel", "age": 23, "employed": false, "married": false]
 ]

我想迭代这些数据并返回一个只包含20岁以上已婚人士的结果。我该怎么做呢？我尝试这样开始：

var adults:Array = []

for person in people {
    for(key:String, value:AnyObject) in person {
        println(person["age"])
    }
}

但后来却陷入了如何继续前进的境地。我还想使用map闭包。我该怎么做？

Answer 1

var people: Array<Dictionary<String, Any>> = [
    ["name":"harry", "age": 28, "employed": true, "married": true],
    ["name":"larry", "age": 19, "employed": true, "married": true],
    ["name":"rachel", "age": 23, "employed": false, "married": false]
]

let oldMarriedPeople = filter(people) { (person: Dictionary<String, Any>) -> Bool in
        let age = person["age"] as Int
        let married = person["married"] as Bool
        return age > 20 && married
}

for p in oldMarriedPeople {
    println(p)
}

Answer 2

let adults = people.filter { person in
    return person["married"] as Bool && person["age"] as Int > 20
}

Answer 3

尝试：

let old = people.filter { person in
    return (person["married"] as NSNumber).boolValue && (person["age"] as NSNumber).intValue > 20
}

由于您使用AnyObject，因此必须将它们用作NSNumbers

或者，您可以将声明更改为Array<Dictionary<String,Any>>并使用：

let old = people.filter { person in
    return person["married"] as Bool && person["age"] as Int > 20
}

过滤一系列词典

3 个答案: