Question

我目前正在将这段代码从mysql转换为PDO：

$catquery = mysql_query("SELECT category, longdescription, locked, 
                                catid, parentcatid, leveldown 
                        FROM ".$tableprefix."fanfiction_categories 
                        WHERE catid = '$catid'") 
                or die(_FATALERROR."Query: SELECT category, locked, catid, parentcatid, leveldown FROM ".$tableprefix."fanfiction_categories WHERE catid = '$catid'<br />Error: (".mysql_errno( ).") ".mysql_error( ));
 $category = mysql_fetch_array($catquery);

我是PDO的新手，但一直在努力学习我的能力。这就是我在PDO中提出的：

$db = new PDO('mysql:host='.$db_host.'; dbname='.$db_name, $db_user, $db_pass); 
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$catquery = $db->prepare("SELECT category, longdescription, locked, catid, 
                                parentcatid, leveldown 
                          FROM ".$tableprefix."fanfiction_categories 
                          WHERE catid=:catid");
$stmt -> bindPARAM (':catid', $catid, PDO::PARAM_STR );
try {
    $stmt->execute ();
    echo "Sucess";
} catch (PDOException $e) {
         echo $e->getMessage();
}

即使在以多种形式尝试之后，我也无法正确获取bindPARAM部分。有什么我可以忽略的吗？我对PDO有点困惑，所以如果有人能指出我在哪里出错，那将会很好。

Answer 1

很简单，您忘记修改复制/粘贴中的所有变量

$db = new PDO('mysql:host='.$db_host.'; dbname='.$db_name, $db_user, $db_pass); 
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$catquery = $db->prepare("SELECT category, longdescription, locked, catid, 
                                parentcatid, leveldown 
                          FROM ".$tableprefix."fanfiction_categories 
                          WHERE catid=:catid");

//$stmt -> bindPARAM (':catid', $catid, PDO::PARAM_STR );
$catquery -> bindPARAM (':catid', $catid, PDO::PARAM_STR );
try {

    //$stmt->execute ();
    $catquery->execute ();

    echo "Sucess";
} catch (PDOException $e) {
         echo $e->getMessage();
}

无法弄清楚我在准备好的陈述中做错了什么

1 个答案: