我想让页面检测是否是星期四,以及是否显示了一些文字。我不明白为什么这不起作用。是因为我可以做=如果比?请解释一下,谢谢!
<!DOCTYPE html>
<html>
<body>
<p id="demo"></p>
<p id="bleh"></p>
<script>
var day;
switch (new Date().getDay()) {
case 0:
day = "Sunday";
break;
case 1:
day = "Monday";
break;
case 2:
day = "Tuesday";
break;
case 3:
day = "Wednesday";
break;
case 4:
day = "Thursday";
break;
case 5:
day = "Friday";
break;
case 6:
day = "Saturday";
}
document.getElementById("demo").innerHTML = "Today is " + day;
</script>
<p id="bleh"></p>
<script>
function myFunction() {
if(new Date().getDay() == 4)
document.getElementById("bleh").innerHTML = "Check your grades.";
}
}
</script>
</body>
</html>
不起作用的部分是这一部分:
<script>
function myFunction() {
if(new Date().getDay() == 4)
document.getElementById("bleh").innerHTML = "Check your grades.";
}
}
</script>
P.S。我会使用OnTime,但是我从github页面托管我的网页,所以我无法在那里加载它,这就是我使用这种类型的JS的原因。
答案 0 :(得分:1)
if (day = 4;) {
请注意您应该使用=
或==
的单个===
。同时删除分号:
if (day === 4) {
同样,正如评论中所指出的那样,你应该把这一天作为一个字符串来检查,因为这就是你设置的内容!
if (day === "Thursday") {
答案 1 :(得分:0)
将日期名称存储在像这样的数组
中会不会更好var days = [
'Sunday',
'Monday',
'Tuesday',
'Wednesday',
'Thursday',
'Friday',
'Saturday'
];
function getCurrentDayName (dayIndex) {
return days[dayIndex];
}
console.log(getCurrentDayName (new Date ().getDay()))
答案 2 :(得分:0)
你可以更容易地得到这样的名字:
# coding: utf8
import json
d = json.loads("""{"mykey": {"readme": "Café"}}""", encoding='latin1')
print d['mykey']['readme'].encode('latin1')
let today = new Date()
demo.innerHTML =
`Today is
${new Intl.DateTimeFormat('en-US', {weekday: 'long'})
.format(today)}`;
let toDay = today.getDay()
bleh.innerHTML =
toDay === 4 ?
'Check your grades.' :
`Not Thursday. Come back in
${(11 - toDay) % 7}
days to re-check.`