Question

我不是百分百肯定如何说出这个问题，所以请随意将问题标题更改为有意义的内容。

我有一个对象solution，其中包含一个属性名days，其中包含10个数组，请参阅下面的示例

{
    "sameShiftHolds": true,
    "sameStaffHolds": true,
    "sameRoomHolds": true,
    "days": [{
        "availableStaff": [
            [0, 1, 4, 3, 5, 9, 22, 44],
            [0, 1, 4, 3, 5, 9, 22, 44],
            [4, 8, 7]
        ],
        "availableRooms": [
            [3, 6, 77, 89, 23],
            [3, 6, 77, 89, 23],
            [2, 7, 9]
        ],
        "suitableStaff": [
            [22, 44],
            [22, 44],
            [4]
        ],
        "suitableRooms": [
            [89, 23],
            [22, 44],
            [2]
        ],
        "ValidStartDate": true
    }, {
        "availableStaff": [
            [0, 1, 4, 3, 5, 9, 22, 44],
            [0, 1, 4, 3, 5, 9, 22, 44],
            [4, 8, 7]
        ],
        "availableRooms": [
            [3, 6, 77, 89, 23],
            [3, 6, 77, 89, 23],
            [2, 7, 9]
        ],
        "suitableStaff": [
            [22, 44],
            [22, 44],
            [4]
        ],
        "suitableRooms": [
            [89, 23],
            [22, 44],
            [2]
        ],
        "ValidStartDate": false
    }, {
        "availableStaff": [
            [0, 1, 4, 3, 5, 9, 22, 44],
            [0, 1, 4, 3, 5, 9, 22, 44],
            [4, 8, 7]
        ],
        "availableRooms": [
            [3, 6, 77, 89, 23],
            [3, 6, 77, 89, 23],
            [2, 7, 9]
        ],
        "suitableStaff": [
            [22, 44],
            [22, 44],
            [4]
        ],
        "suitableRooms": [
            [89, 23],
            [22, 44],
            [2]
        ],
        "ValidStartDate": true
    }, {
        "availableStaff": [
            [0, 1, 4, 3, 5, 9, 22, 44],
            [0, 1, 4, 3, 5, 9, 22, 44],
            [4, 8, 7]
        ],
        "availableRooms": [
            [3, 6, 77, 89, 23],
            [3, 6, 77, 89, 23],
            [2, 7, 9]
        ],
        "suitableStaff": [
            [22, 44],
            [22, 44],
            [4]
        ],
        "suitableRooms": [
            [89, 23],
            [22, 44],
            [2]
        ],
        "ValidStartDate": true
    }, {
        "availableStaff": [
            [0, 1, 4, 3, 5, 9, 22, 44],
            [0, 1, 4, 3, 5, 9, 22, 44],
            [4, 8, 7]
        ],
        "availableRooms": [
            [3, 6, 77, 89, 23],
            [3, 6, 77, 89, 23],
            [2, 7, 9]
        ],
        "suitableStaff": [
            [22, 44],
            [22, 44],
            [4]
        ],
        "suitableRooms": [
            [89, 23],
            [22, 44],
            [2]
        ],
        "ValidStartDate": true
    }, {
        "availableStaff": [
            [0, 1, 4, 3, 5, 9, 22, 44],
            [0, 1, 4, 3, 5, 9, 22, 44],
            [4, 8, 7]
        ],
        "availableRooms": [
            [3, 6, 77, 89, 23],
            [3, 6, 77, 89, 23],
            [2, 7, 9]
        ],
        "suitableStaff": [
            [22, 44],
            [22, 44],
            [4]
        ],
        "suitableRooms": [
            [89, 23],
            [22, 44],
            [2]
        ],
        "ValidStartDate": true
    }, {
        "availableStaff": [
            [0, 1, 4, 3, 5, 9, 22, 44],
            [0, 1, 4, 3, 5, 9, 22, 44],
            [4, 8, 7]
        ],
        "availableRooms": [
            [3, 6, 77, 89, 23],
            [3, 6, 77, 89, 23],
            [2, 7, 9]
        ],
        "suitableStaff": [
            [22, 44],
            [22, 44],
            [4]
        ],
        "suitableRooms": [
            [89, 23],
            [22, 44],
            [2]
        ],
        "ValidStartDate": true
    }, {
        "availableStaff": [
            [0, 1, 4, 3, 5, 9, 22, 44],
            [0, 1, 4, 3, 5, 9, 22, 44],
            [4, 8, 7]
        ],
        "availableRooms": [
            [3, 6, 77, 89, 23],
            [3, 6, 77, 89, 23],
            [2, 7, 9]
        ],
        "suitableStaff": [
            [22, 44],
            [22, 44],
            [4]
        ],
        "suitableRooms": [
            [89, 23],
            [22, 44],
            [2]
        ],
        "ValidStartDate": true
    }, {
        "availableStaff": [
            [0, 1, 4, 3, 5, 9, 22, 44],
            [0, 1, 4, 3, 5, 9, 22, 44],
            [4, 8, 7]
        ],
        "availableRooms": [
            [3, 6, 77, 89, 23],
            [3, 6, 77, 89, 23],
            [2, 7, 9]
        ],
        "suitableStaff": [
            [22, 44],
            [22, 44],
            [4]
        ],
        "suitableRooms": [
            [89, 23],
            [22, 44],
            [2]
        ],
        "ValidStartDate": false
    }, {
        "availableStaff": [
            [0, 1, 4, 3, 5, 9, 22, 44],
            [0, 1, 4, 3, 5, 9, 22, 44],
            [4, 8, 7]
        ],
        "availableRooms": [
            [3, 6, 77, 89, 23],
            [3, 6, 77, 89, 23],
            [2, 7, 9]
        ],
        "suitableStaff": [
            [22, 44],
            [22, 44],
            [4]
        ],
        "suitableRooms": [
            [89, 23],
            [22, 44],
            [2]
        ],
        "ValidStartDate": true
    }]
}

在我的网站上，我有一个星期的自定义日历视图，该视图是从模板创建的，从星期一到星期五开始。默认情况下，有2周但用户可以更改他们想要查看的周数。每个星期都会被一个具有唯一ID "solCol0"，"solCol1"等等的div拆分。

然后我循环选择的周数，在这种情况下我们有2。然后循环遍历solution的长度，在这种情况下为10。我只想循环5次（对于每周的每一天），然后在5次循环之后，将columdId递增1以将细节附加到下一周，例如将前5个循环附加到"solCol0"然后接下来的5个被附加到“solCol1”，如果用户选择了超过2周，到3，solution长度将增加到15，所以接下来的5个循环将附加到“'solCol2”等...

很抱歉，如果这不是很清楚，通常我只需要在每5次循环后增加一个值。任何帮助将不胜感激。

loadSolutionStartRows: function(dates, solution) {
    var self = this;
    for (var i = 0; i < dates.length; i++) {
        var columnId = "#solCol" + i;
        var startDate = moment(dates[i], 'Do MMM');
        var rowDates = [];
        var iterate = 5;
        for (var d = 0; d < solution.days.length; d++) {
            //Every 5 loops - columnId = "#solCol" + i + 1;
            rowDates.push(moment(startDate).format('ddd (Do MMM)'));
            startDate.add(1, 'days');
            var selectedDate = rowDates[d];

            var statusClass;
            var statusIconClass;
            if (solution.days[d].ValidStartDate === true) {
                statusClass = "sxpTableHeaderIconGreenStatus";
                statusIconClass = "octicon " + "octicon-check";
            }
            if (solution.days[d].ValidStartDate === false) {
                statusClass = "sxpTableHeaderIconRedStatus";
                statusIconClass = "octicon " + "octicon-x";
            }


            $(columnId).append(self.solutionTableRow({
                rowId: i + 1,
                date: selectedDate,
                statusClass: statusClass,
                statusIconClass: statusIconClass,
                trainerCountEarly: 1,
                trainerListEarly: 1,
                roomCountEarly: 1,
                roomListEarly: 1,
                trainerCountLate: 1,
                trainerListLate: 1,
                roomCountLate: 1,
                roomListLate: 1
            }));
        }
    }
}

},

使用上面的代码我实现了下面的图像，它增加了10天而不是我想要的5天。

Answer 1

你会想要一个每5次迭代递增一次的变量，所以你需要检查索引是否是5的倍数：

var foo = 0;

for (var i; i < someLength; ++i) {
  if (i % 5 === 0) {
    foo++;
  }
}

这使用模运算符来获取i / 5的余数。如果它是0，那么我们知道索引是5的倍数。

请注意，这绝对是不必要的，也可以只做

Math.floor(someLength / 5);

或者更简洁：

someLength / 5 | 0;

两者都会将除法的结果截断为整数，并且您将知道有多少5 someLength包含。

Answer 2

您可以使用Math.floor(i/5)。它只是将i除以5，然后将其舍入。

对于i的值，从0到4，这将返回1，对于i的值从5到9等，将返回1.

在你的例子中：

 var columnId = "#solCol" + Math.floor(i/5);

Answer 3

对于循环的每一步，检查迭代器是否可被5 if (i % 5 == 0)整除。如果是，请增加columnId变量

Answer 4

就像我评论的那样，你需要一个超出for循环范围的变量，当内循环变量是5的倍数时你可以增加。这是一个例子。

＆＃13;

var outerVar = 0;

for (var innerVar = 1; innerVar <= 10; innerVar++) {
  console.log("Iteration " + innerVar + " uses outerVar " + outerVar + ".");
  if (innerVar % 5 === 0) {
    outerVar++;
  }
}

＆＃13;

for循环每5次迭代递增变量？

4 个答案: