Question

我有以下matlab代码：

clc;
clear all;
close all;
format long;
d=717;              
r1=60000;             
r2=[61043; 62000];             
Rx=[0; 10];                   
Ry=[11.212; 1];              
k=-1.000953;           
for o=1:1:size(Rx)
i=1;
for rho1=0:17.7:d
    for theta=0:10:360;
        rho=rho1;
        x(i)=rho.*cosd(theta)+(Rx(o)*1000);
        y(i)=rho.*sind(theta)+(Ry(o)*1000);
        xx(i)=(((x(i))-(Rx(o)*1000))/d);
        yy(i)=(((y(i))-(Ry(o)*1000))/d);
        l(i)=sqrt(x(i).^2+(y(i)).^2);
        c1=1/r1;
        s11(i)=c1*(l(i).^2);
        s12(i)=1+(sqrt(1-(1+k)*c1*c1*(l(i).^2)));
        s1(i)=s11(i)/s12(i); %hyperbola sag
        s2(i)=(r2(o)-sqrt((r2(o).^2)-(l(i).^2))); %Best fit sag
        m(i)=abs((-s1(i)+s2(i)));
        i=i+1;
    end
end
dz=m';
xn=xx';
yn=yy';
Z=[dz xn yn];
end

每次迭代for循环后，数组dz，xn，yn和矩阵Z都会被修改。如何保存每次迭代的输出？

Answer 1

您可以使用Multidimensional Arrays的概念，如下所示：

    private void button1_Click(object sender, EventArgs e)
    {           
            SerialPort port = new SerialPort("COM4", 9600);
        port.Open();

        byte[] buffer = new byte[2];

        port.Read(buffer, 0, 2);
        HandleSerialData(buffer);

        port.Close();
    }

    private void HandleSerialData(byte[] respBuffer)
    {
        string one, two;
        char a, b;

        a = Convert.ToChar(respBuffer[0]);
        b = Convert.ToChar(respBuffer[1]);

        one = Convert.ToString(a);
        two = Convert.ToString(b);

        MessageBox.Show(one + two);            
    }

保存for循环的每次迭代的数组

1 个答案: