Question

我的桌子有很多列我想在1列上进行分组以获取唯一记录的数量它有大约6亿卢比的数据

我使用查询

select distinct lower(TITLE) , count(lower(TITLE)) as CountOf
from table_name2 
where 
((LENGTH(lower(TITLE)) - LENGTH(replace(lower(TITLE), ' ', '')))+1) > 3
HAVING COUNT(lower(TITLE))>1
group by lower(TITLE)

我如何以有效的方式做到这一点，如果Title是＆＃34;岩石花园区＆＃34;并且它在TITLE字段中存在4次然后我得到它的计数 - ＆gt; 4

Answer 1

你可以试试这个：

select 
 lower(TITLE) , 
 count(lower(TITLE)) as CountOf
from table_name2 
where 
REGEXP_COUNT ('asdaasd  ', '\s')+1 > 3
HAVING COUNT(TITLE)>1
group by TITLE

Answer 2

这应该可以解决问题：

select  TITLE , count(TITLE) as CountOf
from (
    select LOWER(title) title
    from table_name2) t
where TITLE like '% % % %' 
group by TITLE
HAVING COUNT(TITLE)>1

在没有索引的情况下分组大数据

2 个答案: