我是python的新手,并尝试修改csv文件,以便我能够根据给定的列表删除具有特定字段的特定行。 在我当前的代码中,我得到了我想删除的行,但我无法将其删除并将更改保存在同一文件中(替换)。
import os, sys, glob
import time ,csv
# Open a file
path = 'C:\\Users\\tzahi.k\\Desktop\\netzer\\'
dirs = os.listdir( path )
fileslst = []
alertsCode = ("42001", "42003", "42006","51001" , "51002" ,"61001" ,"61002","71001",
"71002","71003","71004","71005","71006","72001","72002","72003","72004",
"82001","82002","82003","82004","82005","82006","82007","83001","84001")
# This would print the unnesscery codes
for file in dirs:
if "ALERTS" in file.upper() :
fileslst.append(file)
fileslst.sort()
with open(fileslst[-1], 'rb') as csvfile:
csvReader = csv.reader(csvfile)
for row in csvReader:
for alert in alertsCode:
if any(alert in row[2] for s in alertsCode) :
print row
任何帮助?
答案 0 :(得分:4)
使用 list comprehension 将所有行读入列表,并排除不需要的行。然后以模式w
(写入模式)将行重写,覆盖或替换文件的内容:
with open(fileslst[-1], 'rb') as csvfile:
csvReader = csv.reader(csvfile)
clean_rows = [row for row in csvReader if not any(alert in row[2] for alert in alertsCode)]
# csvfile.truncate()
with open(fileslst[-1], 'wb') as csvfile:
csv_writer = csv.writer(csvfile)
csv_writer.writerows(clean_rows)