所以我正在制作二元炸弹并且在第4阶段撞到了一堵墙。我看起来像这样：
0x0000000000401175 <+0>: sub $0x18,%rsp
0x0000000000401179 <+4>: lea 0x8(%rsp),%rcx
0x000000000040117e <+9>: lea 0xc(%rsp),%rdx
0x0000000000401183 <+14>: mov $0x402a2d,%esi
0x0000000000401188 <+19>: mov $0x0,%eax
0x000000000040118d <+24>: callq 0x400cb0 <__isoc99_sscanf@plt>
0x0000000000401192 <+29>: cmp $0x2,%eax
0x0000000000401195 <+32>: jne 0x4011a3 <phase_4+46>
0x0000000000401197 <+34>: mov 0x8(%rsp),%eax
0x000000000040119b <+38>: sub $0x2,%eax
0x000000000040119e <+41>: cmp $0x2,%eax
0x00000000004011a1 <+44>: jbe 0x4011a8 <phase_4+51>
0x00000000004011a3 <+46>: callq 0x40171c <explode_bomb>
0x00000000004011a8 <+51>: mov 0x8(%rsp),%esi
0x00000000004011ac <+55>: mov $0x6,%edi
0x00000000004011b1 <+60>: callq 0x40113d <func4>
0x00000000004011b6 <+65>: cmp 0xc(%rsp),%eax
0x00000000004011ba <+69>: je 0x4011c1 <phase_4+76>
0x00000000004011bc <+71>: callq 0x40171c <explode_bomb>
0x00000000004011c1 <+76>: add $0x18,%rsp
0x00000000004011c5 <+80>: retq
我看到它需要两个输入，并且它们似乎在某个值之下。单步执行我只能在第二次输入为2,3或4时跳过第一次爆炸呼叫。似乎在＆lt; + 65＆gt;什么func4返回需要等于12？似乎无论我的第二个数字是否需要等于我的第一个数字，一旦它通过func4。但是我不确定func4是做什么的。我的func4看起来像这样：
0x000000000040113d <+0>: push %r12
0x000000000040113f <+2>: push %rbp
0x0000000000401140 <+3>: push %rbx
0x0000000000401141 <+4>: mov %edi,%ebx
0x0000000000401143 <+6>: test %edi,%edi
0x0000000000401145 <+8>: jle 0x40116b <func4+46>
0x0000000000401147 <+10>: mov %esi,%ebp
0x0000000000401149 <+12>: mov %esi,%eax
0x000000000040114b <+14>: cmp $0x1,%edi
0x000000000040114e <+17>: je 0x401170 <func4+51>
0x0000000000401150 <+19>: lea -0x1(%rdi),%edi
0x0000000000401153 <+22>: callq 0x40113d <func4>
0x0000000000401158 <+27>: lea (%rax,%rbp,1),%r12d
0x000000000040115c <+31>: lea -0x2(%rbx),%edi
0x000000000040115f <+34>: mov %ebp,%esi
0x0000000000401161 <+36>: callq 0x40113d <func4>
0x0000000000401166 <+41>: add %r12d,%eax
0x0000000000401169 <+44>: jmp 0x401170 <func4+51>
0x000000000040116b <+46>: mov $0x0,%eax
0x0000000000401170 <+51>: pop %rbx
0x0000000000401171 <+52>: pop %rbp
0x0000000000401172 <+53>: pop %r12
0x0000000000401174 <+55>: retq
非常感谢任何帮助。