Question

123|china|jack|342|usa|Nick|324345|spin|Amy

我想要这样的最终结果（我知道每3个元素需要一个新行）：

123,china,jack
342,usa,Nick
324345,spin,Amy

谢谢

Answer 1

试试：

x = '123|china|jack|342|usa|Nick|324345|spin|Amy'

l = x.split('|')
new_l = [l[i:i+3] for i in range(0,len(l),3)]

这会给你：

>>> for i in new_l:
...     print ','.join(i)
...
123,china,jack
342,usa,Nick
324345,spin,Amy

更新：阅读文件

要将文件作为字符串读取，请执行以下操作：

with open('your_file.txt', 'r') as myfile:
    x=myfile.read().replace('\n', '|')

Answer 2

可以使用一个print语句

完成

>>> d = '123|china|jack|342|usa|Nick|324345|spin|Amy'
>>> l = d.split('|')
>>> print(*list(map(lambda v: ','.join(v),[l[x: x+3] for x in range(0, len(l), 3)])), sep='\n')
123,china,jack
342,usa,Nick
324345,spin,Amy

所以现在一步一步

>>> d = '123|china|jack|342|usa|Nick|324345|spin|Amy'
>>> l = d.split('|')  # splitting input string into list of str objects that separated with '|'
>>> l
['123', 'china', 'jack', '342', 'usa', 'Nick', '324345', 'spin', 'Amy']
>>> [l[x: x+3] for x in range(0, len(l), 3)]  # combining elements by 3
[['123', 'china', 'jack'], ['342', 'usa', 'Nick'], ['324345', 'spin', 'Amy']]
>>> list(map(lambda v: ','.join(v),[l[x: x+3] for x in range(0, len(l), 3)]))  # merging every sublist to str with ',' as separator
['123,china,jack', '342,usa,Nick', '324345,spin,Amy']
>>> print(*list(map(lambda v: ','.join(v),[l[x: x+3] for x in range(0, len(l), 3)])), sep='\n')  # final print
123,china,jack
342,usa,Nick
324345,spin,Amy

python将一个长字符串拆分成不同的行

2 个答案: